Question

*****PLEASE HELP (30 POINTS)*****

Answer 1

Answer:

2. C) 21.2 yd    3. B) angle IQL    4. B) 55 degree

Step-by-step explanation:

2. The area of an equilateral triangle is given by,

A = $\frac {\sqrt{3} \times a^{2}}{4}$------(1)  where a = length of each side.

Here, a = 7 yd

so , putting a = 7 yd in (1) , we get,

A = $\frac {\sqrt{3} \times 49}{4}$  sq. yd.

  $\simeq 21.2$ sq. yd.

3. B) angle IQL

4. Let, the centre of the circle be at O,

then, ∠DOB = 105°  and ∠BOC = 145° (given)

so, ∠OBD = $\frac{180^{\circ} - \angle DOB}{2}$

                = $\frac{180^{\circ} - 105^{\circ}}{2}$

                = 37.5°  [since the sum of three angles of a triangle  is 180° and OB and OD are two radii of the same circle]

and, similarly, ∠OBC = $\frac{180^{\circ} - \angle COB}{2}$

                = $\frac{180^{\circ} - 145^{\circ}}{2}$

                = 17.5° [since the sum of three angles of a triangle  is 180° and OB and OC are two radii of the same circle]

so,  ∠CBD = ∠OBD + ∠OBC

                 = 37.5° + 17.5°

                 = 55°