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kolezko [41]
3 years ago
7

What is the inverse function of y=x^2+4

Mathematics
1 answer:
user100 [1]3 years ago
8 0

Answer:

  does not exist

Step-by-step explanation:

The inverse relation is found by swapping x and y, then solving for y.

  x = y^2 +4

  x -4 = y^2

  y = ±√(x -4)

This is the inverse relation. Since it is double-valued, it is not a function.

__

The function given does not pass the horizontal line test, so there is no inverse function.

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Solve 0.05p-0.02(5-2p)=0.05(p-2)-0.12
Montano1993 [528]
0.05p-0.02(5-2p)=0.05(p-2)-0.12 

0.05p-0.02(5-2p)=0.05(p-2)-0.12:p 


0.05p-0.1+0.04p=0.05p-0.1-0.12
 
  |Expand \ the \ equation| 

0.09p-0.1=0.05p-0.1-0.12
 
 

0.09p-0.1=0.05p-0.22 


0.09p-0.1-0.05p=-0.22
 

  |Subtract \ 0.05p \ from \ both \ sides| 


0.04p-0.1=-0.22
 
 


0.04p=-0.22+0.1
 
  |Add \ 0.1 \ to \ both \ sides| 


0.04p=-0.12
 
 

0.04p/0.04=-0.12/0.04
  |Divide \ both \ sides \ by \ 0.04| 

p=-3 

\star \ Hence \ Solved
8 0
3 years ago
Write an expression.Then find the 100th term in the sequence. 3,10,17,24,31,38...
Tju [1.3M]
The correct answer would be C
5 0
3 years ago
PLEASE HELPPPPPPPP....?.......
Kobotan [32]

Answer:

a = 9

b = 6

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4 0
2 years ago
Read 2 more answers
If five numbers are selected at random from the set {1,2,3,...,20}, what is the probability that their minimum is larger than 5?
Zanzabum

Answer:

the probability that their minimum is larger than 5 is 0.2373

Step-by-step explanation:

For calculate the probability we need to make a división between the total ways to selected the 5 numbers and the ways to select the five numbers in which every number is larger than 5.

So the number of possibilities to select 5 numbers from 20 is:

<u>20                </u> * <u>      20         </u>*  <u>        20     </u> *<u>        20         </u>* <u>       20 </u>

First number  2nd number   3rd number  4th number   5th number

Taking into account that a number can be chosen more than once, and the order in which you select the numbers matters, for every position we have 20 options so, there are  20^{5} ways to select 5 numbers.

Then the number of possibilities in which their minimum number is larger than 5 is calculate as:

<u>15                </u> * <u>      15         </u>*  <u>           15     </u> *<u>        15          </u>* <u>       15 </u>

First number  2nd number   3rd number  4th number   5th number

This time for every option we can choose number from 6 to 20, so we have 15 numbers for every option and the total ways that satisfy the condition are  15^{5}

So the probability P can be calculate as:

P=\frac{15^{5} }{20^{5} } \\P=0.2373

Then the probability that their minimum is larger than 5 is 0.2373

7 0
3 years ago
Brainliest, thanks, five stars
lutik1710 [3]

Answer:

Option C) 16(0.5x - 0.75y + 2)

Step-by-step explanation:

16(0.5x - 0.75y + 2) = 16*0.5x - 0.75y*16 + 2 *16

                                = 8.0x - 12.0y + 32

                                =  8x - 12y + 32

5 0
3 years ago
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