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DaniilM [7]
3 years ago
9

use the slope formula (m= y2-y1/x2-x1) to find the slope of a line given two points URGENT NEED IT IN 5 MINUTES OR LESS MAYBE A

LIL MORE ITS A CONNECTING THING ON EDGE
Mathematics
1 answer:
nata0808 [166]3 years ago
5 0

Answer:

sdsdssdsdss

Step-by-step explanation:

sdsds

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HELP ME SUPPER FAST PLEASE​
kari74 [83]

Answer:

A) x<-1

Step-by-step explanation:

As the circle is not filled in, we know that the inequality must be > or <.

As the line is to the left of -1 (or lower than it). We know that x must be less than -1

8 0
3 years ago
ANSWER #6 TO BE MARKED AS BRAINLIEST
Alina [70]
I believe its 137/60
3 0
3 years ago
Read 2 more answers
2. Find the measure of angle A to the nearest degree.
pav-90 [236]

Answer:

37°

Step-by-step explanation:

we're going to use cosine rule In calculating for the value of angle A

note that cosine rule can be used when two sides are given with an included angle . from the diagram above, the two sides given are side AB and side AC and the included angle is A

Hence cosine rule

a^2 = AB^2+AC^2 - 2AB×AC Cos A

3.2^2= 2.1^2+4.6^2-2×2.1×4.6COSA

10.24 =4.41+21.16- 19.32 COSA

10.24 = 25.57-19.32COSA

10.24-25.57= -19.32COSA

-15.33= -19.32COSA

dividing bothsides by - 19.32

COSA= -15.33/19.32

COA= 0.79347826

A = COS^-1 (0.79347826)

A= 37.488

A= 37°

<h2>hope this helps!!</h2>
7 0
2 years ago
Instructions: Match each equations with correct type of event.
Mazyrski [523]

The question is incomplete. Below you will find the missing contents.

The correct match of events with order are,

  • P(A)P(B|A) - Dependent event
  • P(A)+P(B) - Mutually exclusive events
  • P(A and B)/P(A) - Conditional events
  • P(A) . P(B) - Independent Events
  • P(A)+P(B) -P(A and B) - not Mutually exclusive events.

When two events A and B are independent then,

P(A and B)=P(A).P(B)

when A and B are dependent events then,

P(A and B) = P(A) . P(B|A)

When two events A and B are mutually exclusive events then,

P(A and B)=0

So, P(A or B) = P(A) + P(B) - P(A and B) = P(A) + P(B)

P(A) + P(B) = P(A or B)

When events are not mutually exclusive then the general relation is,

P(A or B) = P(A) + P(B) - P(A and B)

If the probability of the event B conditioned by A is given by,

\mathrm{P(B|A)=\frac{P(A~and~B)}{P(A)}}

Hence the correct match are -

  • \mathrm{P(A)P(B|A)\rightarrow} Dependent event
  • \mathrm{P(A)+P(B)}\rightarrow Mutually exclusive events
  • \mathrm{\frac{P(A ~and ~B)}{P(A)}\rightarrow} Conditional events
  • \mathrm{P(A) . P(B)\rightarrow} Independent Events
  • \mathrm{P(A)+P(B) -P(A ~and ~B)\rightarrow} not Mutually exclusive events.

Learn more about Probability of Events here -

brainly.com/question/79654680

#SPJ10

5 0
2 years ago
Set up a double integral for calculating the flux of the vector field ????⃗ (????⃗ )=????⃗ , where ????⃗ =⟨x,y,z⟩, through the p
Tema [17]

Answer:

-937.5π

Step-by-step explanation:

F (r) = r = (x, y, z) the surface equation z = 3(x^2 + y^2) z_x = 6x, z_y = 6y the normal vector n = (- z_x, - z_y, 1) = (- 6x, - 6y, 1)

Thus, flux ∫∫s F · dS is given as;

∫∫ <x, y, z> · <-z_x, -z_y, 1> dA

=∫∫ <x, y, 3x² + 3y²> · <-6x, -6y, 1>dA , since z = 3x² + 3y²

Thus, flux is;

= ∫∫ -3(x² + y²) dA.

Since the region of integration is bounded by x² + y² = 25, let's convert to polar coordinates as follows:

∫(θ = 0 to 2π) ∫(r = 0 to 5) -3r² (r·dr·dθ)

= 2π ∫(r = 0 to 5) -3r³ dr

= -(6/4)πr^4 {for r = 0 to 5}

= -(6/4)5⁴π - (6/4)0⁴π

= -937.5π

4 0
4 years ago
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