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VladimirAG [237]
3 years ago
15

A wheel with a diameter of 25 in. is in a puddle of water 8.1 in. deep. What is the width of the wheel, AB, at the surface of th

e water?
Please actually answer the question <3

Mathematics
1 answer:
solniwko [45]3 years ago
8 0

Answer:

The length AB is 23.4in

Step-by-step explanation:

N/B please see the attached detailed diagram for your reference and better understanding

This problem bothers on the mensuration of flat shapes.

The width AB is the chord of the wheel

The radius of the whee r= 25/2= 12.5in

The depth of the wheel in the puddle is 8.1in

Let b be the distance from the surface AB to the diameter

b= 12.5-8.1  = 4.4in

Applying the formula

Chord Length = 2 *√(r²-b²)

=2*√(12.5²-4.4²)

= 2*√(156.25-19.36)

=2*√(136.89

=2*11.7

=23.4in

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Step-by-step explanation:

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Solve the system of equations for x and y.<br> y = x + 5<br> y = 2x + 2
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Explanation:
using the
substitution method
y
=
x
−
5
→
(
1
)
y
=
−
2
x
+
4
→
(
2
)
since both equations are expressed in terms of x we

can equate them
⇒
x
−
5
=
−
2
x
+
4
add 2x to both sides
2
x
+
x
−
5
=
−
2
x
+
2
x
+
4
⇒
3
x
−
5
=
4
add 5 from both sides
3
x
+
5
−
5
=
4
+
5
⇒
3
x
=
9
divide both sides by 3
3
x
3
=
9
3
⇒
x
=
3
substitute this value in
(
1
)
y
=
3
−
5
=
−
2
As a check
substitute these values into
(
2
)
right
=
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4
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2
=
left
⇒
point of intersection
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(
3
,
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2
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