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VladimirAG [237]
4 years ago
15

A wheel with a diameter of 25 in. is in a puddle of water 8.1 in. deep. What is the width of the wheel, AB, at the surface of th

e water?
Please actually answer the question <3

Mathematics
1 answer:
solniwko [45]4 years ago
8 0

Answer:

The length AB is 23.4in

Step-by-step explanation:

N/B please see the attached detailed diagram for your reference and better understanding

This problem bothers on the mensuration of flat shapes.

The width AB is the chord of the wheel

The radius of the whee r= 25/2= 12.5in

The depth of the wheel in the puddle is 8.1in

Let b be the distance from the surface AB to the diameter

b= 12.5-8.1  = 4.4in

Applying the formula

Chord Length = 2 *√(r²-b²)

=2*√(12.5²-4.4²)

= 2*√(156.25-19.36)

=2*√(136.89

=2*11.7

=23.4in

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Simplify each expression then state the coefficient of the variable in each expression <br> X+x+3+4
oksian1 [2.3K]

Answer:

2x +7

The coefficient of the variable is 2

Step-by-step explanation:

x+x+3+4

Combine like terms

2x +7

The coefficient of the variable is 2

6 0
3 years ago
PLEASE HELP I WILL GIVE BRAINLYEST
insens350 [35]

∠13 = 70.5° [Vertically Opposite angles]

∠13+∠14=180° [Linear pair]

70.5°+∠14=180°

∠14=180-70.5

∠14=109.5

∠15=∠14=109.5 [Vertically opposite angles]

∠13=∠12= 70.5° [Co-interior angles]

∠12=∠10= 70.5° [Vertically Opposite angles]

∠14=∠11=109.5 [Co-interior angles]

∠9=∠11= 109.5 [Vertically opposite angles]

∠13=∠7= 70.5° [Alternate interior angles]

∠7=∠5=70.5° [Vertically Opposite angles]

∠7+∠8=180° [Linear Pair]

70.5+∠8=180

∠8=180-70.5

∠8=109.5°

∠8=∠6= 109.5° [Vertically Opposite angles]

∠6=∠3=109.5° [Co-interior angles]

∠7=∠2=70.5° [Co-exterior angles]

∠2=∠4= 70.5° [Vertically Opposite angles]

∠3=∠1= 109.5° [Vertically Opposite angles]

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

<h3>Measures of all angles in sequence⤵️</h3>

  • ∠1= 109.5°
  • ∠2= 70.5°
  • ∠3= 109.5°
  • ∠4= 70.5°
  • ∠5= 70.5°
  • ∠6= 109.5°
  • ∠7= 70.5°
  • ∠8= 109.5°
  • ∠9= 109.5°
  • ∠10= 109.5°
  • ∠11= 70.5°
  • ∠12= 109.5°
  • ∠13= 70.5°
  • ∠14= 109.5°
  • ∠15= 109.5°
  • ∠16= 70.5°
8 0
3 years ago
Read 2 more answers
Due in 10 minutes so
Vilka [71]

Answer:

A

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(not B, C, or D)

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3 years ago
PLEASE HELP
Ilya [14]
In y=mx+b, m= slope and b= y-intercept. All you have to do is substitute.

1)  y= \frac{3}{2} x-2

2) &#10;y=  \frac{-1}{2}x-1

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3 0
3 years ago
Could somebody help me with Geometry? THANKS!!!!!!!!!!!!!!!!!!!!!
Vedmedyk [2.9K]

I'll do problem 1 to get you started.

The answer to problem 1 is <u>3400 miles</u>

============================================================

Explanation for problem 1:

We're asked to find the perimeter, which is the total distance around the exterior or outside. In other words, we need to add up the four side lengths of this quadrilateral.

We'll need the distance formula to find the lengths of the slanted sides AB and BC

----------------------------------------

Let's first find the length of segment AB

A = (x1,y1) = (0,0)

B = (x2,y2) = (400,300)

d = Length of AB

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(0-400)^2 + (0-300)^2}\\\\d = \sqrt{(-400)^2 + (-300)^2}\\\\d = \sqrt{160000 + 90000}\\\\d = \sqrt{250000}\\\\d = 500\\\\

The distance from A to B is 500 miles. This is the same as saying segment AB is 500 miles long.

----------------------------------------

Now find the length of segment BC

B = (x1,y1) = (400,300)

C = (x2,y2) = (-800,800)

d = length of BC

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(400-(-800))^2 + (300-800)^2}\\\\d = \sqrt{(400+800)^2 + (300-800)^2}\\\\d = \sqrt{(1200)^2 + (-500)^2}\\\\d = \sqrt{1440000 + 250000}\\\\d = \sqrt{1690000}\\\\d = 1300\\\\

----------------------------------------

The length of CD is fairly easy to find without needing the distance formula. This is because it is a vertical line. We subtract the y coordinates of C and D to get 800-0 = 800. So CD is 800 miles long.

Segment DA is a similar story. But we subtract the x coordinates. This only works for horizontal lines. DA is 800 miles long because |-800-0| = 800. Absolute value is used to make sure the distance is never negative.

----------------------------------------

To summarize everything so far, we found these four side lengths

  • AB = 500
  • BC = 1300
  • CD = 800
  • DA = 800

The perimeter is going to be the sum of those four sides, leading to...

perimeter = sum of sides

perimeter = AB+BC+CD+DA

perimeter = 500+1300+800+800

perimeter = 3400 miles

This is the total distance traveled if you started at city A, went to B, then to C, then to D, and then finally went back to A.

5 0
3 years ago
Read 2 more answers
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