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Rudiy27
4 years ago
8

Please help me with this question

Mathematics
1 answer:
hichkok12 [17]4 years ago
6 0

Answer:

A

Step-by-step explanation:

Since -8 < 0, we use the top equation which is x^2.

f(-8) = x^2

f(-8) = -8^2

f(-8) = 64

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Two cyclists, 80 miles apart, start riding towards each other at the same time. One cycles three times as fast as the other. If
miv72 [106K]

Answer:

The speed of the faster cyclist is 15 miles per hour

Step-by-step explanation:

Let the speed of the slower cyclist be x miles per hour

The speed of the faster is 3 times this

Mathematically, we have this as 3 * x miles per hour = 3x miles per hour

Now;

distance = speed * time

In 4 hours, the distance covered by the slower will be;

x * 4 = 4x miles

The faster;

3x * 4 = 12x miles

Since they are riding opposite each other, they would have covered a total distance of 80 miles when they meet

Thus, we have that;

12x + 4x = 80

16x = 80

x = 80/16

x = 5

The speed of the faster is;

3x miles per hour

Substitute the value of x here

That will be;

3 * 5 = 15 miles per hour

8 0
3 years ago
PLEASEEEEEEE HELP ME! WILL GIVE 20 POINTS AND BRAINLIEST
mart [117]

Answer:

a - 50/100

b - 9/4

c - 27/8

Step-by-step explanation:

Scale: 50/100

Ratio: 36/16 = 18/8 = 9/4

Ratio: 216/64 = 108/32 = 54/16 = 27/8

3 0
3 years ago
Evaluate the expression for x =5 and y= 1 (x-7y)²<br><br> pretty confused
sveticcg [70]

Answer:

-4

Step-by-step explanation:

So since x=5 and y= 1 the new expression would be 1(5-7) to the second power. Using pemdas, 5-7 is -2. -2 to the second power is -4. negative 4 times 1 is negative 4.

5 0
3 years ago
Read 2 more answers
10. Determine the open interval(s) on which the function f(x) = 12x - x^3 is increasing.
Gre4nikov [31]

Answer:

\large\boxed{x\in(-2,\ 2)}

Step-by-step explanation:

f(x)=12x-x^3

Calculate the derivative of the function:

f'(x)=\left(12x-x^3\right)'=(12x)'-\left(x^3\right)'=12-3x^2

Calculate the zeros of the derivative:

f'(x)=0\Rightarrow12-3x^2=0\qquad\text{add}\ 3x^2\ \text{to both sides}\\\\3x^2=12\qquad\text{divide both sides by 3}\\\\x^2=4\to x=\pm\sqrt4\\\\x=\pm2

Let's check the derivative sign:

f'(x)>0\iff12-3x^2>0\qquad\text{use the distributive property}\\\\-3(x^2-4)>0\\\\-3(x^2-2^2)>0\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\-3(x-2)(x+2)>0\\^{\qquad x=2\qquad x=-2

Sketch a parabola open down

(before the brackets there is the number -3 < 0)

Look at the picture.

Where the derivative is negative, the function decreases.

Where the derivative is positive, the function increases.

Therefore your answer is:

x\in(-2,\ 2)

3 0
4 years ago
Simplify using order of operations. Show all of your work and do one operation at a time to receive all possible points. 16 ÷ 4
Ugo [173]
First you do 16/4
Which is 4
And then you do that times 2
4*2 equals 8
The answer is 8
7 0
4 years ago
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