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3 years ago

What does 3 squared equal?

Mathematics

1 answer:

Helen [10]3 years ago

7 0

3 squared =9

Hope this helps.

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Find the equation of the line that is perpendicular to y = –4x + 8 and passes though the point (–12, 4). A) y = – 1 4 x + 7 B) y

____ [38]

Answer:

Step-by-step explanation:

perp: 1/4

y - 4 = 1/4(x + 12)

y - 4 = 1/4x + 3

y = 1/4x + 7

answer is C

6 0

3 years ago

A light bulb consumes 15300 watt-hours in 4 days and 6 hours . How many watt-hours does it consume per day?

Kay [80]

Answer:

3600 per 24 hour period or 1 day.

Step-by-step explanation:

24 x 15300/(4 x 24+6)=3600

5 0

3 years ago

Read 2 more answers

The Venn diagram shows the results of two events resulting from rolling a number cube.

tankabanditka [31]

Answer:

$P(A|B)=\frac{2}{3}$

$P(A)*P(B)=\frac{1}{3}$

$P(A) =\frac{2}{3}$

$P(B) =\frac{1}{2}$ .

Step-by-step explanation:

We use the Venn diagram to calculate the desired probabilities.

Note that there are 6 possible results in the sample space

S = {1, 2, 3, 4, 5, 6}

Then note that in the region representing the intercept of A and B there are two possible values.

$P (A\ and\ B) = \frac{2}{6} = \frac{1}{3}$

In the region that represents event A there are 4 possible outcomes {4, 5, 1, 2}

$P(A) = \frac{4}{6} = \frac{2}{3}$

In the region that represents event B there are 3 possible outcomes {1, 2, 6}

$P(B) = \frac{3}{6} = \frac{1}{2}$ .

Now

$P(A | B)=\frac{P(A \ and\ B)}{P(B)}\\\\P(A | B)=\frac{\frac{1}{3}}{\frac{1}{2}}\\\\P(A|B)=\frac{2}{3}$

$P(A)*P(B)=\frac{2}{3}*\frac{1}{2}=\frac{1}{3}$

6 0

4 years ago

(ab^2 x -b^4a^3)^2<br><br> What is the answers

Umnica [9.8K]

Answer:

$\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8$

Step-by-step explanation:

Given the expression

$\left(ab^2\:x\:-b^4a^3\right)^2$

solving the expression

$\left(ab^2\:x\:-b^4a^3\right)^2$

$\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2$

$a=ab^2x,\:\:b=b^4a^3$

so the expression becomes

$=\left(ab^2x\right)^2-2ab^2xb^4a^3+\left(b^4a^3\right)^2$

$=a^2b^4x^2-2a^4b^6x+a^6b^8$

Thus,

$\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8$

3 0

3 years ago

Solve<br><img src="https://tex.z-dn.net/?f=%7B2x%7D%5E%7B2%7D%20%20%2B%208x%20-%201%20%3D%200" id="TexFormula1" title="{2x}^{2}

kramer

Answer:

x= ± $3\sqrt{2} /2$ +2

Step-by-step explanation:

Use the formula ( b/2) ^2 in order to create a new term. Solve for x by using this term to complete the square.

x= ± $3\sqrt{2} /2$ +2

4 0

1 year ago