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Nat2105 [25]
3 years ago
7

Will GIVE 200 Points!!! NEED HELP ASAP!!!! PLEASE HURRY AND HELP!!! For the given statement, write the converse, inverse, and co

ntrapositive.
If a figure is a cube, then it has eight vertices.
Mathematics
1 answer:
UNO [17]3 years ago
7 0

Answer:

See explanation

Step-by-step explanation:

Consider given statement "If a figure is a cube, then it has eight vertices" in math terms. Let

  • statement p be "A figure is cube.";
  • statement q be "A figure has 8 vertices."

Then the statement  "If a figure is a cube, then it has eight vertices"  can be written as

p\Rightarrow q

Converse (q\Rightarrow p): If a figure has eight vertices, then it is a cube.

Inverse (\neg p\Rightarrow \neg q): If a figure is not a cube, then it has not eight vertices.

Contrapositive (\neg q\Rightarrow \neg p): If a figure has not eight vertices, then it is not a cube.

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aev [14]
If the wall with 4 ft. of storage area can fit 6 sections of plant and the wall with 7 ft. Can fit 5, that means each section is 3 ft. because 7-4=3, so that extra section on the wall with 4 ft. You do this because there is one extra section on the wall with four. Knowing this, the wall with 7 ft. Would be the 7 ft. + 5 sections of 3 ft. So 7+(5x3) = 22. On the wall with 4 ft., do the same,
4+(6x3) =22. Since they are equal and the walls are supposed to be equal, we can confirm this is the right answer
6 0
3 years ago
Plz help me it’s emergency
BaLLatris [955]

Answer:

idk

Step-by-step explanation:

1/4 can also be written as .25

1 divided by 4 is .25

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3 0
3 years ago
2^sinx+2^cosx find the minimum value of this trignometry
Anit [1.1K]
Take the deritiivive
ln(2)cos(x)2^{sin(x)}-ln(2)sin(x)2^{cos(x)}
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evaluate origial at 5pi/4
2^{sin(5pi/4)}+2^{cos(5pi/4)}=
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5 0
3 years ago
The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.
Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

(c) 0

Step-by-step explanation:

Let <em>X</em> denote the heights of women in the USA.

It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0
3 years ago
Is r(l+2h) a formula for a length area or volume
Novosadov [1.4K]
Hello,

In my opinion, 
I would say Volume. 

I hope this helps.
4 0
3 years ago
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