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Elena-2011 [213]
3 years ago
13

Given: measure of arc PIV = 7/2 times measure of arc PKV PKV Find: m∠VPJ

Mathematics
1 answer:
Serhud [2]3 years ago
6 0

Answer:

Measure of angle 'VPJ' is 140 degrees.

Step-by-step explanation:

Given:

Measure of arc 'PIV' and measure of arc 'PKV'.

'PIV' = 7/2 times of 'PKV'

Lets say that PKV is 'x'.

⇒ m(PIV)=\frac{7}{2} \times x

⇒ m(PIV)=3.5x

Note:

A full circle has an arc angle measure of 360.

So,

⇒ 3.5x+x=360

⇒ 4.5x=360

⇒ x=\frac{360}{4.5}

⇒ x=80

The measure of arc 'PKV' = 80 degrees.

We have to find angle 'VPJ' that is having a linear pair with angle 'VPL'.

So before finding we 'VPJ' have to find 'VPL'.

And

According to the theorem:

The angle formed by the tangent and the chord is half the measure of the intercepted arc.

Then.

⇒ \angle VPL=\frac{m\ arc\ (PKV)}{2}

⇒ \angle VPL=\frac{80}{2}

⇒ \angle VPL=40 degrees

⇒ And from linear pair .

⇒ m\angle VPL +m \angle VPJ =180

⇒ 40 +m \angle VPJ =180

⇒ m \angle VPJ =180-40

⇒ m \angle VPJ =140 degrees.

So measure of angle 'VPJ' is 140 degrees.

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16/8 would be classified as a/an?<br> A:whole number <br> B:integer <br> C:Rational Number
gregori [183]

Answer:

Whole Number

Step-by-step explanation:

Numerator. This is the number above the fraction line. For 16/8, the numerator is 16.

Denominator. This is the number below the fraction line. For 16/8, the denominator is 8.

Improper fraction. This is a fraction where the numerator is greater than the denominator.

Mixed number. This is a way of expressing an improper fraction by simplifying it to whole units and a smaller overall fraction. It's an integer (whole number) and a proper fraction.

Now let's go through the steps needed to convert 16/8 to a mixed number.

Step 1: Find the whole number

We first want to find the whole number, and to do this we divide the numerator by the denominator. Since we are only interested in whole numbers, we ignore any numbers to the right of the decimal point.

16/8 = 2

Now that we have our whole number for the mixed fraction, we need to find our new numerator for the fraction part of the mixed number.

Step 2: Get the new numerator

To work this out we'll use the whole number we calculated in step one (2) and multiply it by the original denominator (8). The result of that multiplication is then subtracted from the original numerator:

16 - (8 x 2) = 0

Step 3: Our mixed fraction

We've now simplified 16/8 to a mixed number. To see it, we just need to put the whole number together with our new numerator and original denominator:

2 (0/8)

You maybe have noticed here that our new numerator is actually 0. Since there is no remainder, we can remove the entire fraction part of this mixed number, leaving us with a final answer.

8 0
3 years ago
Find the surface area S of the following cylinder.
Tanya [424]

Answer:

384π

Step-by-step explanation:

From the diagram,

Diameter ( d ) = 16

Height ( h ) = 16

To find : Surface area of Cylinder = ?

Radius ( r ) = ?

Formula : -

r = d / 2

r = 16 / 2

r = 8

Formula : -

Surface area of Cylinder = 2πr ( r + h )

Surface area of Cylinder = 2πr ( r + h )

= 2π x 8 ( 8 + 16 )

= 16π x 24

Surface area of Cylinder = 384π

4 0
3 years ago
Determine if each of the following sets is a subspace of Pn, for an appropriate value of n.
snow_tiger [21]

Answer:

1) W₁ is a subspace of Pₙ (R)

2) W₂ is not a subspace of Pₙ (R)

4) W₃ is a subspace of Pₙ (R)

Step-by-step explanation:

Given that;

1.Let W₁ be the set of all polynomials of the form p(t) = at², where a is in R

2.Let W₂ be the set of all polynomials of the form p(t) = t² + a, where a is in R

3.Let W₃ be the set of all polynomials of the form p(t) = at² + at, where a is in R

so

1)

let W₁ = { at² ║ a∈ R }

let ∝ = a₁t² and β = a₂t²  ∈W₁

let c₁, c₂ be two scalars

c₁∝ + c₂β = c₁(a₁t²) + c₂(a₂t²)

= c₁a₁t² + c²a₂t²

= (c₁a₁ + c²a₂)t² ∈ W₁

Therefore c₁∝ + c₂β ∈ W₁ for all ∝, β ∈ W₁  and scalars c₁, c₂

Thus, W₁ is a subspace of Pₙ (R)

2)

let W₂ = { t² + a ║ a∈ R }

the zero polynomial 0t² + 0 ∉ W₂

because the coefficient of t² is 0 but not 1

Thus W₂ is not a subspace of Pₙ (R)

3)

let W₃ = { at² + a ║ a∈ R }

let ∝ = a₁t² +a₁t  and β = a₂t² + a₂t ∈ W₃

let c₁, c₂ be two scalars

c₁∝ + c₂β = c₁(a₁t² +a₁t) + c₂(a₂t² + a₂t)

= c₁a₁t² +c₁a₁t + c₂a₂t² + c₂a₂t

= (c₁a₁ +c₂a₂)t² + (c₁a₁t + c₂a₂)t ∈ W₃

Therefore c₁∝ + c₂β ∈ W₃ for all ∝, β ∈ W₃ and scalars c₁, c₂

Thus, W₃ is a subspace of Pₙ (R)

8 0
3 years ago
What is the integer for -22 + (-16) =
natka813 [3]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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What one should I choose I'm stumped ??
Karolina [17]
The second one is the best answer in my opinion i'm not sure.
8 0
3 years ago
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