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andrezito [222]
3 years ago
15

Question 5

Mathematics
1 answer:
galina1969 [7]3 years ago
7 0

Answer:b 1/2

Step-by-step explanation:

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Sedaia [141]

The two lines are parallel, no matter how long they travel they will not cross.

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3 years ago
Prime factorization of 125
VladimirAG [237]
The prime factorization of 125 is 5 x 5 x 5. This is a unique list of the prime factors, along with their multiplicities. Note that the prime factorization of 125 does not include the number 1, yet it does include every instance of a certain prime factor. 125 is a composite number. Hope this helps you out! :)
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3 years ago
PLZ HELP ASAP!! (Algebra)
svp [43]

Answer:

Rational, integers, whole, natural, real

Step-by-step explanation:

109 is rational because it can be expressed as the ratio of two integers: 109:1

109 is integer because it can be written with no fractions

109 is a whole number because it has no decimals

109 is natural because it is an integer greater than 0

Hope this helps! ;)

6 0
3 years ago
OI 00<br>R<br>b) From the given figure:<br>write the alternate<br>angle of angle RUN<br>P<br>$<br>2​
Ainat [17]

Answer:

alternate angle to angle RUN is angle POU

Step-by-step explanation:

Alternate angles are defined as angles that are located in opposite positions when we look at them relative to a transverse line that intersects two horizontal lines.

Now, we want to find the alternate angle to angle RUN.

The same transverse line cuts the other horizontal line PQ at point O.

Therefore the alternate angle to angle RUN is angle POU

7 0
3 years ago
Integrate ​G(x,y,z)equalsz over the parabolic cylinder yequalszsquared​, 0less than or equalsxless than or equals2​, 0less than
yKpoI14uk [10]

I gather you're supposed to compute the integral of G(x,y,z)=z over a surface S that is the part of the parabolic cylinder y=z^2 with 0\le x\le2 and 0\le z\le\frac{\sqrt{15}}2.

We can parameterize S by

\vec s(x,z)=x\,\vec\imath+z^2\,\vec\jmath+z\,\vec k

with the given constraints on x and z. Take the normal vector to S to be

\vec s_x\times\vec s_z=-\vec\jmath+2z\,\vec k

so that the surface element is

\mathrm dS=\|\vec s_x\times\vec s_z\|\,\mathrm dx\,\mathrm dz=\sqrt{1+4z^2}\,\mathrm dx\,\mathrm dz

Then in the integral, we have

\displaystyle\iint_Sz\,\mathrm dS=\int_0^2\int_0^{\sqrt{15}/2}z\sqrt{1+4z^2}\,\mathrm dz\,\mathrm dx=\boxed{\frac{21}2}

5 0
3 years ago
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