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Brilliant_brown [7]
2 years ago
5

The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass

. Starting with 190 grams of a radioactive isotope, how much will be left after 4 half-lives?
Mathematics
1 answer:
Semmy [17]2 years ago
5 0
190*(1/2)^4 = 190/16 = 11.875 . . . grams
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Marcel has $40 to spend on amusement park rides. Tickets cost $1.50 without special membership pass, or $1.25 with a membership
aniked [119]
He should, because he would get two more tickets.  

To prove this, do this:
Divide $40 by 1.5 to get 26.6666666666666666667 (Ignore the .666666666667, just use 26 because you can't buy part of a ticket.)

Now subtract 5 from $40 to get the amount with the membership pass. You will get 35.  Divide 35 by 1.25 to get 28.  Marcel will get 2 more tickets if he buys the pass.

6 0
2 years ago
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Find the value of x. Round your answer to the nearest tenth.<br><br> sin 46(degrees)=x/14
Lostsunrise [7]
sin 46^{o} = \frac{x}{14}  \\ x=14sin 46^{o} \\ =14 \times 0.7193 \\ =10.1
6 0
3 years ago
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Which of the following are identities? Check all that apply.
gulaghasi [49]

Answer:

A B and C

Step-by-step explanation:

Hopefully this helps

6 0
3 years ago
Baby Amelia's parents measure her height every month.
jonny [76]

The statement H(30) = H(25) + 5 means that, "when Amelia was 30 months old, she was 5 centimeters taller than when she was 25 months old"

<h3><u>Solution:</u></h3>

Given that,

Baby Amelia's parents measure her height every month

It is given that H(t) models Amelia's height (in centimeters) when she was "t" months old

Given statement is H(30) = H(25) + 5

So, we can say that H(30) = Amelia's height when she was 30 months old

H(25) = Amelia's height when she was 25 months old

So H(30) = H(25) + 5 means that,

Height of Amelia when she was 30 months old is 5 centimeter more than Amelia height when she was 25 years old

Or we can say that,

When Amelia was 30 months old, she was 5 centimeters taller than when she was 25 months old

7 0
3 years ago
Two-digit natural numbers are formed, with replacement, from the digits 0 through 9.
alexdok [17]

Answer:

The first digit of a two digit number can be any of digits 1 - 9. It cannot be 0 though. Therefore there are 9 possible digits for the first place.

There are 5 possible digits for the second position. The two digit number has to be odd and therefore the final digit must be 1,3,5,7 or 9

Therefore for each and every one of the nine first digits there are 5 digits that the second can be.

Therefore ANSWER = 9 * 5 = 45 possible permutations.

2. The largest two digit number = 99

Subtract 57 and you get 42

ANSWER = 42

The forty two numbers are 58 ,59, 60, 61......98, 99

7 0
3 years ago
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