All categories

3 years ago

How do I do this please help me I will give you thank even tho it’s not important Ahahah please help me

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

4 0

Answer:

(-2 , 5)

(-1 , 0)

(1 , -4)

(3 , 0)

(4 , -5)

Step-by-step explanation:

First solve the equation:

x² - 2x - 3

Find two numbers with have a sum of -2 and a product of -3.

-3 and 1

(x - 3)(x + 1)

Solve for x:

x - 3 = 0

x = 3

x + 1 = 0

x = -1

You know that the graph will cross the x-axis at -1 and 3.

(-1 , 0)

(3 , 0)

You know that the graph is positive.

Complete the square to find the vertex

x² - 2x - 3

(x - 1)² = x² - 2 + 1

x² - 2x - 3 = x² - 2 + 1 - 2 = (x - 1)² - 2

1 = 0

x = 1

Substitute into the original equation:

x² - 2x - 3 =

1² - (2 * 1) - 3 =

1 - 2 - 3 =

-4

(1 , -4)

You can input any two numbers within -10 and 10. Such as -2 and 4.

x² - 2x - 3 =

-2² - (2 * -2) - 3 =

4- -4- 3 =

(-2 , 5)

x² - 2x - 3 =

4² - (2 * 4) - 3 =

16 - 8 - 3 =

-5

(4 , -5)

You might be interested in

I'm completely lost?

aliya0001 [1]

13000-5600=7400...that's about it, just multiply then subtract

4 0

3 years ago

Read 2 more answers

Please help ASAP!!!!!!!!

JulijaS [17]

The correct answer is: "The value of the 5 in 50.8 is 1,000 times the value of the 5 in 18.35."

Step-by-step explanation:

When numbers are considered, their position or place value matters a lot.

When a decimal number is written, moving left from the decimal point the place value increases ten times and while moving to the right the place value decreases 10 times.

Given two numbers are:

50.8 and 18.35

In order to compare the 5 in both numbers we have to find the place value of 55 in both numbers.

So,

In 50.8:

The place value of 5 in 50.8 is: 50

In 18.35:

The place value of 5 will be: 5/100

To compare the values, we will divide the larger place value by smaller place value

$=\frac{50}{\frac{5}{100}}\\\\=\frac{50*100}{5}\\\\= \frac{5000}{5}\\\\=1000\ times$

Hence,

The correct answer is: "The value of the 5 in 50.8 is 1,000 times the value of the 5 in 18.35."

Keywords: Place value, decimals

Learn more about place values at:

#LearnwithBrainly

4 0

3 years ago

Which equation represents a population of 250 animals that decreases at an annual rate of 21% ?

victus00 [196]

Answer: Choice C. p = 250(0.79)^t

Work Shown:

p = a*b^t

p = a*(1+r)^t

p = 250*(1+(-0.21))^t

p = 250(0.79)^t

Note that r = -0.21 is negative to indicate we have exponential decay.

3 0

2 years ago

Let X1 and X2 be independent random variables with mean μand variance σ².

My name is Ann [436]

Answer:

a) $E(\hat \theta_1) =\frac{1}{2} [E(X_1) +E(X_2)]= \frac{1}{2} [\mu + \mu] = \mu$

So then we conclude that $\hat \theta_1$ is an unbiased estimator of $\mu$

$E(\hat \theta_2) =\frac{1}{4} [E(X_1) +3E(X_2)]= \frac{1}{4} [\mu + 3\mu] = \mu$

So then we conclude that $\hat \theta_2$ is an unbiased estimator of $\mu$

b) $Var(\hat \theta_1) =\frac{1}{4} [\sigma^2 + \sigma^2 ] =\frac{\sigma^2}{2}$

$Var(\hat \theta_2) =\frac{1}{16} [\sigma^2 + 9\sigma^2 ] =\frac{5\sigma^2}{8}$

Step-by-step explanation:

For this case we know that we have two random variables:

$X_1 , X_2$ both with mean $\mu = \mu$ and variance $\sigma^2$

And we define the following estimators:

$\hat \theta_1 = \frac{X_1 + X_2}{2}$

$\hat \theta_2 = \frac{X_1 + 3X_2}{4}$

Part a

In order to see if both estimators are unbiased we need to proof if the expected value of the estimators are equal to the real value of the parameter:

$E(\hat \theta_i) = \mu , i = 1,2$