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3 years ago

Determine which quadratic equation has two non-real solutions.

Mathematics

1 answer:

LekaFEV [45]3 years ago

3 0

Answer:

Hello,

answer C : -3x²-3x-2=0 (or 3x²+3x+2=0)

Step-by-step explanation:

A: delta=12²-4*2*18=0 not negative

B: delta= 5²+4*3*1=37 not negative

C: 3x²+2x+2=0, delta=2²-4*3*2=16-24=-8 is negative: roots are complex

D: delta 16²-4*2*2=240 not negative

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PLEASE HELP QUICK!! (25 Points) Name the postulate or theorem you can use to prove the triangles congruent.

Akimi4 [234]

Hello!

You know that two sides and one of the angles are congruent

The only choice that has two sides and 1 angle is ASA postulate

The answer is ASA postulate

Hope this helps!

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4 years ago

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A line passes through (0,4) and (3,0). Which equation does not represent the equation of this line?

Olenka [21]

Answer:

Step-by-step explanation:

use both points to find the slope using the equation

y2-y1/x2-x1, so , -2-4/2-0 = -6/2 = -3. slope or m = -3

then the y int can be any y point, so either -2 or 4. in this case they used 4.

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3 years ago

Which congruence theorems can be used to prove ΔABR ≅ ΔACR? Select three options.

sergejj [24]

Answer:

1. HL

2. SAS

3. SSS

Step-by-step explanation:

Triangles ABR and ACR share side AR (hypotenuse of two right triiangles).

Angles ABR and ACR are right angles.

Sides AB and AC are congruent.

Sides BR and CR are congruent.

1. You can use HL theorem, because two triangles have congruent pair of legs and congruent hypotenuses.

2. You can use SAS theorem, because two triangles have two pairs of congruent legs and a pair of included right angles between these legs.

3. You can use SSS theorem, because two triangles have two pairs of congruent legs and congruent hypotenuses.

4 0

3 years ago

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Sandra plays a matching game. In order to advance to the next level, she must score at least 10 points. She scores 18 points for

serious [3.7K]

Answer:

Yes

Step-by-step explanation:

she scored 18 points, then minus 6. She would have 12. She made it to the next level

5 0

3 years ago

Tompkins Associates reports that the mean clear height for a Class A warehouse in the United States is 22 feet. Suppose clear he

coldgirl [10]

Given Information:

Mean clear height = μ = 22 feet

Standard deviation of clear height = σ = 4 feet

Required Information:

a) P(X > 16) = ?

b) P(X < 14) = ?

c) P(25 < X < 30) = ?

Answer:

a) P(X > 16) = 93.12%

b) P(X < 14) = 2.27%

c) P(25 < X < 30) = 20.39%

Step-by-step explanation:

What is Normal Distribution?

We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.

a) We want to find out the probability that the clear height is greater than 16 feet.

$P(X > 16) = 1 - P(X < 16)\\\\P(X > 16) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\P(X > 16) = 1 - P(Z < \frac{16 - 22}{4} )\\\\P(X > 16) = 1 - P(Z < \frac{-6}{4} )\\\\P(X > 16) = 1 - P(Z < -1.5)\\\\$

The z-score corresponding to -1.5 is 0.0668

$P(X > 16) = 1 - 0.0668\\\\P(X > 16) = 0.9312\\\\P(X > 16) = 93.12 \%$

Therefore, the probability that the clear height is greater than 16 feet is 93.12%

b) We want to find out the probability that the clear height is less than 14 feet

$P(X < 14) = P(Z < \frac{x - \mu}{\sigma} )\\\\P(X < 14) = P(Z < \frac{14 - 22}{4} )\\\\P(X < 14) = P(Z < \frac{-8}{4} )\\\\P(X < 14) = P(Z < -2)\\\\$

The z-score corresponding to -2 is 0.02275

$P(X < 14) = 0.02275\\\\P(X < 14) = 2.27 \%$

Therefore, the probability that the clear height is less than 14 feet is 2.27%

c) We want to find out the probability that the clear height is between 25 and 30 feet.

$P(25 < X < 30) = P( \frac{x - \mu}{\sigma} < Z < \frac{x - \mu}{\sigma} )\\\\P(25 < X < 30) = P( \frac{25 - 22}{4} < Z < \frac{30 - 22}{4} )\\\\P(25 < X < 30) = P( \frac{3}{4} < Z < \frac{8}{4} )\\\\P(25 < X < 30) = P( 0.75 < Z < 2 )\\\\$

The z-score corresponding to 0.75 is 0.7734 and 2 is 0.9773

$P(25 < X < 30) = P( Z < 2 ) - P( Z < 0.75 ) \\\\P(25 < X < 30) = 0.9773 - 0.7734 \\\\P(25 < X < 30) = 0.2039\\\\P(25 < X < 30) = 20.39 \%$

Therefore, the probability that a child spends more than 4 hours and less than 8 hours per day unsupervised is 20.39%

How to use z-table?

Step 1:

In the z-table, find the two-digit number on the left side corresponding to your z-score. (e.g 1.5, 2.2, 0.5 etc.)

Step 2:

Then look up at the top of z-table to find the remaining decimal point in the range of 0.00 to 0.09. (e.g. if you are looking for 1.50 then go for 0.00 column)

Step 3:

Finally, find the corresponding probability from the z-table at the intersection of step 1 and step 2.

6 0

3 years ago