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3 years ago

Help please homework due tomorrow and I don't know how to do this

Mathematics

2 answers:

vlabodo [156]3 years ago

5 0

1)point a:0.20 point b : 0.70
2)point c:0.53

Furkat [3]3 years ago

4 0

Number 1 is 0.2 and 0.4
number 2 is 0.53 and 0.56
number 3 is on the 0.3
number 4 is 1/3
number 5 is a little bit before the 0.7 mark
number 6 is 62/100

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In the last year, a total of 2727 earthquakes occurred in the country. Of these, 85.3 % were minor tremors with magnitudes of

Komok [63]

Answer:

Minor earthquakes occurred in the country in the last year were 2326.

Step-by-step explanation:

Given:

In the last year, a total of 2727 earthquakes occurred in the country.

Of these, 85.3 % were minor tremors with magnitudes of 3.9 or less on the Richter scale.

Now, to find the minor earthquakes occured in the country last year.

Total earthquakes occurred in the country = 2727.

The percent of minor earthquakes = 85.3%.

Now, to get the number of minor earthquakes:

85.3% of 2727.

$=\frac{85.3}{100} \times 2727.$

$=\frac{232613.1}{100}$

$=2326.131$

The number of minor earthquakes nearest whole number = 2326.

Therefore, minor earthquakes occurred in the country in the last year were 2326.

3 0

3 years ago

Crash testing is a highly expensive procedure to evaluate the ability of an automobile to withstand a serious accident. A simple

Veseljchak [2.6K]

Answer:

The 95% confidence interval is (-0.2451, 06912)

Step-by-step explanation:

From the question, we have;

The number of small cars in the sample of small cars, n₁ = 12

The number of small cars that were totaled, x = 8

The number of large cars in the sample of small cars, n₂ = 15

The number of large cars that were totaled, y = 5

Therefore, the proportion of small cars that were totaled, pX = x/n₁

∴ pX = 8/12 = 2/3

The proportion of large cars that were totaled, pY = y/n₁

∴ pY = 5/15 = 1/3

The 95% confidence interval for the difference pX - pY is given as follows;

$pX-pY\pm z^{*}\sqrt{\dfrac{pX\left (1-pX \right )}{n_{1}}+\dfrac{pY\left (1-pY \right )}{n_{2}}}$

$\dfrac{2}{3} -\dfrac{1}{3} \pm 1.96 \times \sqrt{\dfrac{\dfrac{2}{3} \times \left (1-\dfrac{2}{3} \right )}{12}+\dfrac{\dfrac{1}{3} \times \left (1-\dfrac{1}{3} \right )}{15}}$

Therefore, we have;

$\therefore 95\% \ CI = \dfrac{1}{3} \pm 0.3578454$

The 95% confidence interval, CI = (-0.2451, 06912)

6 0

2 years ago

50 POINTS

aleksandrvk [35]

Answer:

thats only 25

Step-by-step explanation:

7 0

3 years ago

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Help this is due today!!!!!!!

oee [108]

The answer I believe is 5 because 2 vases hold 10 red roses and 5 yellow roses. But since the person has 3 vases but it has to be the same amount as the first person. They would both have 30 flowers in their vases. But then each of the vases has 6 red roses so you just do 30 divided by 6 and you get 5.

4 0

3 years ago

Use the net to find the lateral area of the cylinder

Elena L [17]

Answer:

The answer to your question is: A = 282.6 in²

Step-by-step explanation:

Data

height = 9 in

radius = 5 in

Formula

A = 2πrh

Process

A = 2(3.14)(5)(9)

A = 282.6 in²

4 0

3 years ago

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