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Lunna [17]
3 years ago
5

What is the least whole number “x” for which 2x > 11?

Mathematics
1 answer:
Akimi4 [234]3 years ago
5 0

Answer:

6

Step-by-step explanation:

Simplifying inequalities is almost the same as simplifying equations. So, in this case, we can divide both sides by two to isolate the variable x:

2x > 11

÷2    ÷2

x > 5.5

Now, we need to find the least whole number of x that makes the expression above true. The next whole number greater than 5.5 is 6, so 6 is the least whole number x for which the inequality holds true.

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Answer:

a = 1/2 (1 ±sqrt(47))

Step-by-step explanation:

a^2-a+12=0

We will complete the square

Subtract 12 from each side

a^2-a+12-12=0-12

a^2-a=-12

The coefficient of a = -1

-Divide by 2 and then square it

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Add it to each side

a^2 -a +1/4=-12 +1/4

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(a-1/2)^2= -47/4

Take the square root of each side

sqrt((a-1/2)^2) =sqrt(-47/4)

a-1/2 = ±i sqrt(1/4) sqrt(47)

a-1/2= ±i/2 sqrt(47)

Add 1/2 to each side

a-1/2+1/2 = 1/2± i/2 sqrt(47)

a =  1/2± i/2 sqrt(47)

a = 1/2 (1 ±sqrt(47))

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