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Svetach [21]
4 years ago
9

A coordinate grid with 2 lines. One line, labeled f(x) passing through (negative 2, 4), (0, 2), and the point (1, 1). The other

line is labeled g(x) and passes through (negative 3, negative 3), (0, 0) and the point (1, 1). Which input value produces the same output value for the two functions on the graph? x = −1 x = 0 x = 1 x = 2
Mathematics
2 answers:
Margarita [4]4 years ago
4 0

Answer:

x = 1

Step-by-step explanation:

The line 1 passing  through the points (-2,4), (0,2) and (1,1) is represented by the function f(x).

Again the line 2 is represented by y = g(x) and it passes through the points (-3,-3), (0,0) and (1,1).

So the only common point between line 1 and line 2 is (1,1) and it will be unique since two straight lines meet at only one point if they are not parallel.

Hence, for x = 1 input value produces the same output value y = 1 for the two functions f(x) and g(x) on the graph. (Answer)

sesenic [268]4 years ago
4 0

Answer:

X=-1

Step-by-step explanation:

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Which statement best describes the triangle formed by joining the points A(-3,6),B(-11,2),C(-4,-2)
Vikki [24]

Answer:

Isosceles triangle

Step-by-step explanation:

Length of side AB = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

                              = \sqrt{(-11+3)^2+(2-6)^2}

                              = \sqrt{64+16}

                              = \sqrt{80}

                              = 4\sqrt{5}

Length of BC = \sqrt{(-4+11)^2+(-2-2)^2}

                      = \sqrt{49+16}

                      = \sqrt{65}

Length of AC = \sqrt{(-3+4)^2+(6+2)^2}

                      = \sqrt{1+64}

                      = \sqrt{65}

Since, AC = BC, ΔABC will be an isosceles triangle.

6 0
3 years ago
Karl ran 4 blocks in 15 minutes. He then ran 1 more block. What is a reasonable value for the amount of time it took him to run
irakobra [83]
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The area of a right triangle is 336 cm². The base of the right triangle is 48 cm.
Flauer [41]
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This gives you 14 cm for the unknown side
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(48)^2 + (14)^2 = c^2
2304 + 196 = c^2
2500 = c^2
The square root of 2500 is 50 so the length of the hypotenuse is 50

5 0
4 years ago
HURRYYY!!
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Answer:

The middle one

Step-by-step explanation:

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Answer:

4

Step-by-step explanation:

2 added by another 2, results in 4

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3 years ago
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