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3 years ago

Multiply (3x2-4x+5)(x2-3x+2)

1 answer:

7 0

So with this, you can rewrite the equation as: $(3x^2\times x^2)+(3x^2\times -3x)+(3x^2\times 2)+(-4x\times x^2)+(-4x\times -3x)+(-4x\times 2)+(5\times x^2)+(5\times -3x)+(5\times 2)$

Firstly, solve the multiplication: $3x^4+(-9x^3)+6x^2+(-4x^3)+12x^2+(-8x)+5x^2+(-15x)+10$

Next, combine like terms, and your answer will be: $3x^4-13x^3+23x^2-23x+10$ 

You might be interested in

The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in

Anon25 [30]

We have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is $[2,\infty)$ .

If we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

Let us know find its inverse.

$y=(x-5)^{2}+2$

Upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

Let us now solve this function for y.

$(y-5)^{2}=x-2\\
y-5=\pm \sqrt{x-2}\\
y=5\pm \sqrt{x-2}\\$

Hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .

8 0

2 years ago

0.09X+4=4.9 I need to solve the unknown

saul85 [17]

Answer:

the answer should be x=10

5 0

3 years ago

(K3+2k2-82k-28)/(k+10)

Ne4ueva [31]

So for this, we will be using synthetic division. To set it up, have the equation so that the divisor is -10 (since that is the solution of k + 10 = 0) and the dividend are the coefficients. Our equation will look as such:

(Note that synthetic division can only be used when the divisor is a 1st degree binomial)

-10 | 1 + 2 - 82 - 28
---------------------------

Now firstly, drop the 1:

-10 | 1 + 2 - 82 - 28
↓
-------------------------
1

Next, you are going to multiply -10 and 1, and then combine the product with 2.

-10 | 1 + 2 - 82 - 28
↓ - 10
-------------------------
1 - 8

Next, multiply -10 and -8, then combine the product with -82:

-10 | 1 + 2 - 82 - 28
↓ -10 + 80
-------------------------
1 - 8 - 2

Next, multiply -10 and -2, then combine the product with -28:

-10 | 1 + 2 - 82 - 28
↓ -10 + 80 + 20
-------------------------
1 - 8 - 2 - 8

Now, since we know that the degree of the dividend is 3, this means that the degree of the quotient is 2. Using this, the first 3 terms are k^2, k, and the constant, or in this case k² - 8k - 2. Now what about the last coefficient -8? Well this is our remainder, and will be written as -8/(k + 10).

Putting it together, the quotient is $k^2-8k-2-\frac{8}{k+10}$ 

8 0

2 years ago

Slope and your-intercept of y+2x=4

Kruka [31]

Y+2x=4 To get the answer subtract the 2x from both sides making it y = -2x+4 the slope is -2 and the y-intercept is 4

5 0

3 years ago

Question

shusha [124]

Answer:

5x cars

Step-by-step explanation:

(# of cars washed) = (# cars washed per day)(# of days)

= (x/day) * (5 days) = 5x

cars

5 0

3 years ago