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cluponka [151]
3 years ago
15

Multiply (3x2-4x+5)(x2-3x+2)

Mathematics
1 answer:
Iteru [2.4K]3 years ago
7 0

So with this, you can rewrite the equation as: (3x^2\times x^2)+(3x^2\times -3x)+(3x^2\times 2)+(-4x\times x^2)+(-4x\times -3x)+(-4x\times 2)+(5\times x^2)+(5\times -3x)+(5\times 2)

Firstly, solve the multiplication: 3x^4+(-9x^3)+6x^2+(-4x^3)+12x^2+(-8x)+5x^2+(-15x)+10

Next, combine like terms, and <u>your answer will be: 3x^4-13x^3+23x^2-23x+10</u>

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Given that 6 &gt; –2, which statements are true? Check all that apply.
USPshnik [31]
First sixth and seventh are true
3 0
3 years ago
Read 2 more answers
If you plotted the points in the table and connected
castortr0y [4]

Answer:

U shaped.

Step-by-step explanation:

When x = 0 , f(x) = 6

when x =1 yf(x) = 0

when x = 2 f(x) = -2

x = 3 f(x) = 0

x = 4 f(x) = 6.

So the graphs falls from the left and rises to the right in the form of a U.

You can draw a rough graph to confirm this.

3 0
3 years ago
Chris &amp; Maya are looking at three companies in the motorbike industry- Honda, Hero &amp; Yamaha. They identified three stren
luda_lava [24]

Answer:

1/ Zamaha

2/ Hero

3/ Honda

Step-by-step explanation:

unweighted method is used which means the 3 mearsure are accounted for the same poportion in competitive strength assesment, 1/3 for each criteria.

So, we caculate the avergae points of each brand;

  • Honda = 1/3*(7+5+8) = 20/3
  • Hero = 1/3*(8+6+7) = 21/3
  • Zamaha = 1/3*(6+8+9) = 23/3

The order of the companies from highest to lowest is:

1/ Zamaha

2/ Hero

3/ Honda

4 0
4 years ago
P(Q) = 12/17<br> P(R) = 3/8<br> If Q and Rare independent events, find the PQ and R).
kodGreya [7K]

Answer:

9/34

Step-by-step explanation:

P(QnR) = P(Q) * P(R)

= 12/17 * 3/8

= 9/34

6 0
2 years ago
Using the GCF you found in Part B, rewrite 72 + 81 as two factors. One factor is the GCF and the other is the sum of two numbers
konstantin123 [22]

72|2\\36|2\\18|2\\.\ 9|3\\.\ 3|3\\.\ 1|\\\\72=2\cdot2\cdot2\cdot\boxed{3}\cdot\boxed{3}\\\\81|3\\27|3\\.\ 9|3\\.\ 3|3\\.\ 1|\\\\81=\boxed{3}\cdot\boxed{3}\cdot3\cdot3\\\\GCF(72,\ 81)=\boxed{3}\cdot\boxed{3}=9\\\\72=9\cdot8\\81=9\cdot9\\\\\boxed{72+81=9(8+9)}

8 0
4 years ago
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