The area of a square is (side)².
If the area is 128m², then the side is (√128) meters. (That's 8√2.)
The diagonal is the hypotenuse of the right triangle you get
if you slice the square in half along the diagonal. Its length is
given in the words of Old Pythagoras:
c² = a² + b²
'a' and 'b' are sides of the square, so
c² = (√128)² + (√128)²
= 2 (√128)²
c = √ (2 x 128) = √256 = 16 meters .
Answer:
The absolute value of any number will always be positive meaning that if you start with a positive number the sum of its absolute value will not be zero. Although if you start out with a negative number the sum of its absolute value will be zero.
Step-by-step explanation:
I'd start by writing an equation for each of the right triangles. (Pythagorean theorem)
y² + 9² = z²
x² + z² = (4+9)²
4² + y² = x²
we want to find z so combine the equations by substituting the other variables x,y out.
substitute y² for (x² - 4²) in 1st equation.
(x² - 4²) + 9² = z²
now by rearranging the 2nd equation we can substitute x² for (13² - z²)
(13² - z²) - 4² + 9² = z²
169 - z² - 16 + 81 = z²
234 - z² = z²
234 = 2z²
234/2 = z²
117 = z²
√(117) = z
√(9*13) = z
3√(13) = z
13 goes in the box
Answer:
Step-by-step explanation:
We first need to know the square root of I then add 10 on that square root since r is 10 more than the square root of I
Therefore,
The answer is A) √3
cot(-5π/6)=1/tan(-5π/6)
=1/tan(-(5π/6)
Use the property: tan(-x)=-tan(x)
=1/tan(5π/6)
-(1/tan(5π/6))
tan(5π/6)=-√3/3
-(1/-√3/3)
-(1/-√3/3)
=√3
