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2 years ago

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Uche pumps gasoline at a rate of 18\,\dfrac{\text{L}}{\text{min}}18 min L 18, start fraction, start text, L, end text, divided

by, start text, m, i, n, end text, end fraction. What is Uche's pumping rate in \dfrac{\text{mL}}{\text{s}} s mL start fraction, start text, m, L, end text, divided by, start text, s, end text, end fraction?

1 answer:

Fiesta28 [93]2 years ago

8 0

Answer:

Uche's pumping rate is <u>300 mL/s</u>.

Step-by-step explanation:

Given:

Uche pumps gasoline at a rate of 18 L/min.

Now, to find Uche's pumping rate in mL/s.

The rate at which Uche pumps gasoline = 18 L/min.

So, to get the pumping rate in mL/s we use convert L/min to mL/s by using conversion factor:

<u>1 L/min = 16.6667 mL/s.</u>

18 L/min = 16.6667 × 18 mL/s.

18L/min = 300 mL/s.

Therefore, Uche's pumping rate is 300 mL/s.

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