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scZoUnD [109]
3 years ago
10

The Toyota Camry is one of the best-selling cars in North America. The cost of a previously owned Camry depends on many factors,

including the model year, mileage, and condition. To investigate the relationship between the car’s mileage and the sales price for Camrys, the following data show the mileage and sale price for 19 sales (PriceHub web site, February 24, 2012).Miles(1000s) Price($1,000s) 22 16.2 29 16.0 36 13.8 47 11.5 63 12.5 77 12.9 73 11.2 87 13.0 92 11.8 101 10.8 110 8.3 28 12.5 59 11.1 68 15.0 68 12.2 91 13.0 42 15.6 65 12.7 110 8.3A. Test whether each of the regression parameters b0 and b1 are equal to zero at 0.01 level of significance.B. What are the correct interpretations of the estimated regression parameters?C. Are these interpretations reasonable?

Mathematics
1 answer:
Hatshy [7]3 years ago
5 0

Answer:

Step-by-step explanation:

Hello!

Given the variables

Y: Cost of a previously owned Camry.

X: Mileage of a previously owned Camry.

Scatter plot in attachment.

As you can see in the scatter plot, the price of the previously owned Camry decreases as their mileage increases this suggest that there is a negative linear regression between these two variables.

Hypothesis test for the y-intercept

H₀: β₀ = 0

H₁: β₀ ≠ 0

Level of significance α: 0.01

p-value < 0.0001

The decision is to reject the null hypothesis. You can conclude that the population mean of the cost of a previously owned Camry, when the mileage is zero, is different from zero.

H₀: β = 0

H₁: β ≠ 0

Level of significance α: 0.01

p-value: 0.0003

The decision is to reject the null hypothesis. You can conclude that the population mean of the cost of a previously owned Camry is modified when the mileage increases in one unit.

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The mayor of Chicago is known for being a great host, and he puts a lot of time into preparing for events. For the mayor's next
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Answer:

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Step-by-step explanation:

Given,

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3 years ago
How would you describe the shape of the normal distribution?
RUDIKE [14]

The shape of the normal distribution is bell shape and it is also symmetrical from the left and right sides about the origins (mean).

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A normal distribution is a function on some random variables, which represent the set of all those random variables in a symmetrical bell shape about the mean value.

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It is also known as probability distribution curve.

The normal distribution has two parameters:

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What is the shape of the normal distribution?

The normal distribution curve is at it's peak at the mean value. This shows that the probability of occurrence of the data or value is more concentrated or distributed about the mean. It is also symmetric about the mean. As we more further from the mean, we see that the normal distribution curve gradually decreases showing that the probability of occurrence of the data or the values decreases. The shape that this curve forms is like a bell-shaped. So the shape of normal distribution is bell shape.

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1 year ago
there are 28 tables in the cafeteria.each table has 12 students sitting at it.fourth graders sit at 13 of the yables.fifth grade
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Hope this helps!

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6 0
3 years ago
I need to know the improper fractions answers for:
zmey [24]

Answer:

Part 1) x=\frac{15}{2}\ units

Part 2) z=\frac{15\sqrt{3}}{2}\ units

Part 3) y= \frac{15\sqrt{3}}{4}\ units

Part 4) b= \frac{45}{4}\ units

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

cos(60^o)=\frac{x}{15} ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

cos(60^o)=\frac{1}{2}

substitute

\frac{1}{2}=\frac{x}{15}

solve for x

x=\frac{15}{2}\ units ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

15^2=x^2+z^2

substitute the value of x

15^2=(\frac{15}{2})^2+z^2

solve for z

z^2=15^2-(\frac{15}{2})^2

z^2=225-\frac{225}{4}

z^2=\frac{675}{4}

z=\frac{\sqrt{675}}{2}\ units

simplify

z=\frac{15\sqrt{3}}{2}\ units

step 3

Find the value of y

In the right triangle of the right

sin(30^o)=\frac{y}{z} ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

sin(30^o)=\frac{1}{2}

so

\frac{1}{2}=y:\frac{15\sqrt{3}}{2}

solve for y

\frac{1}{2}= \frac{2y}{15\sqrt{3}}

y= \frac{15\sqrt{3}}{4}\ units

step 4

Find the value of b

In the right triangle of the right

cos(30^o)=\frac{b}{z} ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

cos(30^o)=\frac{\sqrt{3}}{2}

so

\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}

solve for y

\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}

b= \frac{45}{4}\ units

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3 years ago
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