Answer:
The question is written kinda bad, so i take the next two assumptions:
The original line is:
y = 5*x + 23
And we want to find a perpendicular line that passes through the point (-40, 2012)
Suppose that we have a linear equation:
y = a*x + b
A perpendicular line to this one, will have a slope equal to -(1/a)
Then a random perpendicular line to the one above, is:
y = -(1/a)*x + c
In this case, we start with the line:
y = 5*x + 23
Then the family of perpendicular lines to this one, will be like:
y = (-1/5)*x + c
Where c can be any real number.
Now, we also want this line to pass through (-40, 2012)
This means that when x = -40, the value of y must be 2012
We could replace these values in our equation above and solve it for c.
2012 = -(1/5)*(-40) + c
2012 = 40/5 + c
2012 = 8 + c
2012 - 8 = c = 2004
Then the equation is:
y = -(1/5)*x + 2004.
Answer: (x - 3)² + (y + 0.5)² = 3.25 → ![(x-3)^2+\bigg(y+\dfrac{1}{2}\bigg)^2=\dfrac{13}{4}](https://tex.z-dn.net/?f=%28x-3%29%5E2%2B%5Cbigg%28y%2B%5Cdfrac%7B1%7D%7B2%7D%5Cbigg%29%5E2%3D%5Cdfrac%7B13%7D%7B4%7D)
<u>Step-by-step explanation:</u>
Concentric means they have the same center but different radii.
The equation of a circle is: (x - h)² + (y - k)² = r² where
- (h, k) is the center of the circle
- r is the radius of the circle
Complete the square to find the center of the circle
x² - 6x + _____ + y² + y + _____ = 1 + ____ + ____
↓ ↓
-6/2 = -3 1/2 = 1/2
Equation: (x - 3)² + (y + 1/2)² = r²
Since the circle passes through point (x, y) = (4, -2), input that into the equation to find r².
(x - 3)² + (y + 1/2)² = r²
(4 - 3)² + (-2 + 1/2)² = r²
(1)² + (-3/2)² = r²
1 + 9/4 = r²
13/4 = r²
Equation: (x - 3)² + (y + 1/2)² = 13/4 → ![(x-3)^2+\bigg(y-\dfrac{1}{2}\bigg)^2=\dfrac{13}{4}](https://tex.z-dn.net/?f=%28x-3%29%5E2%2B%5Cbigg%28y-%5Cdfrac%7B1%7D%7B2%7D%5Cbigg%29%5E2%3D%5Cdfrac%7B13%7D%7B4%7D)
In decimal form: (x - 3)² + (y + 0.5)² = 3.25
15 times.
5 times 15 equals 75
Answer:
is it true or fules
Step-by-step explanation:
Answer:
100
Step-by-step explanation:
20 times 100 equals 2000