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3 years ago

Pls help with question.

Mathematics

1 answer:

BigorU [14]3 years ago

4 0

Answer:

4a) 4 1/6

4b) 2

5a) 36.424

5b) 5.4

Step-by-step explanation:

When multiplying or dividing by mixed numbers, convert them into improper and just do it from left to right for each numerator and denominator

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if ABC is a isosceles triangle with sides(2a+b)cm, (6a+2b+1)cm and a base of 4a cm, if it's perimeter is 28 find sides

Katyanochek1 [597]

Answer:

a=1.5, b= 3

Step-by-step explanation:

sum of all sides will give us perimeter. Therefore

2a+b+6a+2b+1+4a=28

12a+3b+1=28

12a+3b=27....eqn1

since t two sides of this isosceles triangle are equal:

2a+b=4a

2a=b

$a=\frac{b}{2}$

substituting $\frac{b}{2}$ $.$ in the first equation whenever we encounter a we will have:

$12(\frac{b}{2})+3b=27\\$

6b+3b=27

9b=27

b=3

therefore $a= \frac{b}{2} =\frac{3}{2} =1\frac{1}{2} or 1.5$

7 0

2 years ago

A square park measures 170 feet along each side. Two paved paths run from each corner to the opposite corner and extend 3 feet i

Cerrena [4.2K]

Answer:

The total area, in square feet, taken by the paths is 2,004

Step-by-step explanation:

see the attached figure with lines to better understand the problem

I can divide the figure into four right triangles, one small square and four rectangles

step 1

Find the area of the right triangle of each corner of the path

The area of the triangle is

$A=(1/2)(b)(h)$

substitute the given values

$A=(1/2)(3)(3)=4.5\ ft^2$

step 2

Find the hypotenuse of the right triangle

Applying Pythagoras Theorem

Let

d -----> hypotenuse of the right triangle

$d^{2}=3^{2}+3^{2}$

$d^{2}=18$

$d=\sqrt{18}\ ft$

simplify

$d=3\sqrt{2}\ ft$

The hypotenuse of the right triangle is equal to the width of the path

step 2

Find the area of the small square of the path

The area is

$A=b^{2}$

we have

$b=3\sqrt{2}\ ft$ ----> the width of the path

substitute

$A=(3\sqrt{2})^{2}$

$A=18\ ft^2$

step 3

Find the length of the diagonal of the square park

Applying Pythagoras Theorem

Let

D -----> diagonal of the square park

$D^{2}=170^{2}+170^{2}$

$D^{2}=57,800$

$D=\sqrt{57,800}\ ft$

simplify

$D=170\sqrt{2}\ ft$

step 4

Find the height of each right triangle on each corner

The height will be equal to the width of the path divided by two, because is a 45-90-45 right triangle

$h=1.5\sqrt{2}\ ft$

step 5

Find the area of each rectangle of the path

The area of rectangle is $A=LW$

we have

$W=3\sqrt{2}\ ft$ ----> width of the path

Find the length of each rectangle of the path

$L=(D-2h-d)/2$

where

D is the diagonal of the park

h is the height of the right triangle in the corner

d is the width of the path (length side of the small square of the path)

substitute the values

$L=(170\sqrt{2}-2(1.5\sqrt{2})-3\sqrt{2})/2$

$L=(170\sqrt{2}-3\sqrt{2}-3\sqrt{2})/2$

$L=(164\sqrt{2})/2$

$L=82\sqrt{2}\ ft$

Find the area of each rectangle of the path

$A=LW$

we have

$W=3\sqrt{2}\ ft$

$L=82\sqrt{2}\ ft$

substitute

$A=(82\sqrt{2})(3\sqrt{2})$

$A=492\ ft^2$

step 6

Find the area of the paths

Remember

The total area of the paths is equal to the area of four right triangles, one small square and four rectangles

substitute

$A=4(4.5)+18+4(492)=2,004\ ft^2$

therefore

The total area, in square feet, taken by the paths is 2,004

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3 years ago

The three-dimensional shape in the diagram on the right is a cube.

user100 [1]

Answer:

Step-by-step explanation:

To answer this question, you should cut this cube and see these two square faces that these lines are drawed as I show on the upload...

These lines represents a 45º of angle and the sum of them is 90º.

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Answer:

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Step-by-step explanation:

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