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Softa [21]
3 years ago
10

BRAINLEST?! ☺️ What are the features of the quadratic function graphed in the figure?

Mathematics
1 answer:
n200080 [17]3 years ago
8 0

Answer:

C

Step-by-step explanation:

The minimum point is (3, -4). Therefore, vertex = (3, -4).

The curve intersects the x-axis at (1,0) and (5,0). Therefore, the x-intercepts are (1,0) and (5,0).

The curve intersects the y-axis at (0,5). Therefore, the y-intercept is (0,5).

As the curve changes from decreasing to increasing at x = 3, there is an axis of symmetry at x = 3.

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The slope of the line below is 1.5. Write the equation of the line in point-slope form, using the coordinates of the labeled poi
Nataly [62]
Point slope form equation: y - y1 = m(x - x1)
in this case

y - 3 = 1.5(x - 4)

Answer
Point slope form equation:
y - 3 = 1.5(x - 4)
5 0
3 years ago
What is the density of an object having a mass of 25 g and a volume of 8.0 cm cubed
weqwewe [10]

Answer:

3.125 g/cm³.

Step-by-step explanation:

The formula for density/mass/volume is d = m/v, where d is density in grams per cm cubed, m is in grams, and v is in cm cubed.

In this case, m = 25 and v = 8.0.

d = 25 / 8.0

d = 25 / 8

d = 3.125.

So, the density of the object is 3.125 g/cm cubed.

Hope this helps!

6 0
3 years ago
Write an equation in slope-intercept form for the line passing through the pair of points.
Umnica [9.8K]
First find your slope! by doing
y2-y1/x2-x1
in this case it would be
2-(-3)/-1-(-6)
It would give you 5/5 which would reduce to 1 meaning your slope equals 1
with your slope now you should use the point slope formula y-y1=m(x-x1)

i’m going to use the point (-1,2) so the equation would be

y-2=1(x-(-1))

simplifying that you would get

y-2=1x+1

then put it in y=mx+b form and get

y=x+3
8 0
3 years ago
How do I multiply (4-√2)(5+√3)
bonufazy [111]

Answer:

17.4076456756

Step-by-step explanation:


6 0
3 years ago
Point B has coordinates ​(3​,2​). The​ x-coordinate of point A is −6. The distance between point A and point B is 15 units. What
xxTIMURxx [149]

Answer:

Distance between two points= √(x2-x1)²+(y2-y1)²

D= 15units

Let "k" be the y-coordinate of A

A(-6,k)

B(3,2)

15= √(3--6)²+(2-k)²

Taking square of both sides to eliminate the square root.

15²=(9)²+(2-k)²

225=81+4-4k+k²

k²-4k - 140=0

Using Quadratic Formula to evaluate

k= 14 or k=-10

The Possible coordinates of A are

(-6,14) or (-6,-10)

4 0
2 years ago
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