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Ratling [72]
2 years ago
9

Y is the midpoint of WZ. X is the midpoint of WY . XY =2. What is the length of WZ?

Mathematics
1 answer:
mamaluj [8]2 years ago
4 0

Using the given information, the length of WZ is 8

<h3>Length of a line </h3>

From the question, we are to find the length of WZ

From the given information,

Y is the midpoint of WZ

and

X is the midpoint of WY

First,

We will create a line that models the given description

<u>W             X                Y                                 Z</u>

                         2

From the given information,

XY = 2

Since X is the midpoint of WY

Then,

WX = XY

∴ WX = 2

Thus

WY = WX + XY

WY = 2 + 2

WY = 4

Also,

Y is the midpoint of WZ

Then,

WY = YZ

∴ YZ = 4

Thus,

WZ = WY + YZ

WZ = 4 + 4

WZ = 8

Hence, the length of WZ is 8

Learn more on Calculating length of a line here: brainly.com/question/13191885

#SPJ1

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Driving under the influence of alcohol (DUI) is a serious offense. The following data give the ages of a random sample of 50 dri
o-na [289]

Answer:

Explanation below.

Step-by-step explanation:

For this case we have the following dataset:

46, 16, 41, 26, 22 ,33, 30, 22 ,36, 34,

63, 21, 26, 18, 27, 24, 31, 38, 26, 55,

31,  47, 27, 43 ,35, 22 ,64,40, 58, 20,

49, 37, 53, 25, 29, 32, 23, 49, 39, 40,

24, 56, 30, 51, 21, 45, 27, 34, 47, 35

So we have 50 values. The first step on this case would be order the dataset on increasing way and we got:

16, 18, 20, 21, 21, 22, 22, 22, 23, 24,

24, 25, 26, 26, 26, 27, 27, 27, 29, 30

30, 31, 31, 32, 33, 34, 34, 35, 35, 36,

37, 38, 39, 40, 40, 41, 43, 45, 46, 47,

47, 49, 49, 51, 53, 55, 56, 58, 63, 64

We can find the range for this dataset like this:

Range = Max-Min = 64-16 =48

Then since we need 7 classes we can find the length for each class doing this:

W = \frac{48}{7}=6.86

And now we can define the classes like this and counting how many observations lies on each interval we got the frequency:

  Class           Frequency      Midpoint           RF                   CF

________________________________________________

[16-22.86)              8               19.43         (8/50)=0.16           0.16

[22.86-29.71)         11              26.29        (11/50)=0.22          0.38

[29.71-36.57)         11               33.14         (11/50)=0.22          0.6

[36.57-43.43)         7               40.0          (7/50)=0.14           0.74

[43.43-50.29)        6               46.86        (6/50)=0.12          0.86

[50.29-57.14)         4               53.72        (4/50)=0.08         0.94

[57.14-64]               3               60.57        (3/50)=0.06           1.0

________________________________________________

Total                         50                                         1.00

RF= Relative frequency. CF= Cumulative frequency

The relative frequency was calculated as the individual frequency for a class divided by the total of observations (50)

The mid point is the average between the limits of the class.

And the cumulative frequency is calculated adding the relative frequencies for each class.

8 0
4 years ago
I need help ASAP. Last Assignment for this class.
german

Answer:

a squared plus b squared equals c squared

Step-by-step explanation the answer either your in for a bumpy ride

4 time 3=12

7 0
3 years ago
Read 2 more answers
What is the square root of 1200?
alukav5142 [94]
<span>34.6410161514 is the answer

Hope this helped :)</span>
4 0
3 years ago
Read 2 more answers
Find the value of each variables
BigorU [14]

Answer:

<em>X=11</em>

<em>y=22</em>

Step-by-step explanation:

tan60\frac{11\sqrt{3} }{x} \\\\\sqrt{3} =\frac{11\sqrt{3} }{x} \\\\x=\frac{11\sqrt{3} }{\sqrt{3} }

⇒x=11

Sib 60=\frac{11\sqrt{3} }{y} \\\\\frac{\sqrt{3} }{2} =\frac{11\sqrt{3} }{y} \\\\y=\frac{11\sqrt{3} }{\sqrt{\frac{3}{2} } }

⇒ y=22

<u>hope it helps....</u>

8 0
3 years ago
A) write 600 as product of prime factors give your answer in index form
SpyIntel [72]

Answer: (a) 2³ ˣ 3 ˣ 5², 2 ˣ 3 ˣ 5² = 150

Step-by-step explanation:

This is problems on common factors.

(a) 600 = 2 × 2 × 2 × 3 × 5 × 5

       = 2³ˣ 3 ˣ 5²

(b)   The highest common factors could be calculated using factors methods and the divisional methods.

Here we go.

(i)   600  = 2³ ˣ 3 ˣ 5²

     1050 = 2 ˣ 3 ˣ 5² ˣ 7, the highest common factor HCF will be

      HCT = 2 ˣ 3 ˣ 5²

               = 150.

The divisional methods.

     600) 1050 ( 1

            -  600

                ------

                450 ) 600 ( 1

                       -  450

                          ------

                           150 ) 450 ( 3

                                  - 450

                                    ------

                                     000

     So the answer is 150, the principle is that you continue to divide and subtract until you arrive at zero.

Answer = 150

         

4 0
3 years ago
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