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3 years ago

What is 5 + 2^3 divided by 4 - 2

Mathematics

2 answers:

V125BC [204]3 years ago

5 0

Answer:

Step-by-step explanation:

5+ $2^{3}$ /4-2

$2^{3}$ = 2 x 2 x 2 (12)

5+ 12 / 4-2

5 + 3 - 2

Mariana [72]3 years ago

3 0

Answer:

6.5 or 13/2

Step-by-step explanation:

$\frac{5 + {2}^3{} }{4 - 2}$

First find what 2^3 power is.

$\frac{5 + 8}{4 - 2}$

Then, just add the top and bottom

$\frac{13}{2}$

This in decimal form is 6.5

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David is filling out orders for an online business and gets paid $1 for each order he fills out plus bonus of 25 cents per order

svp [43]

Answer:

David will make $481 (he earns the bonus)

Explanation:

If he makes $1 for each order and he filled out 385 orders, then why can't we say he made $385?

Because of this statement rights here:

"...and gets paid $1 for each order he fills out plus bonus of 25 cents per order if the average number of orders he completes per day within any of the given weeks exceeds 20."

So we need to find out if any of the 3 weeks has an average of 20+ orders per day.

<h2>David is filling out orders for an online business and gets paid $1 for each order he fills out</h2>

(x is the amount of orders he fills out)

profit = $1x

<h2>plus bonus of 25 cents per order if the average number of orders he completes per day within any of the given weeks exceeds 20. </h2>

if any average orders per day is > 20 in any week

bonus profit = $1.25x

<h2>The ratio of the number of orders he processed during the first week to the number of orders he processed during the second week is 3:2, </h2>

first week second week

3a : 2a

<h2>while the the ratio that compares the number of orders he filled out during the first and the third weeks is 4 to 5 respectively. </h2>

first week third week

4a : 5a

<h2>What amount of money will David make at the end of three weeks if the total number of orders he filled out was 385?</h2>

sum of all ratios of a = 385

So we have

3a : 2a (first week to second week)

4a : 5a (first week to third week)

Notice how the first two numbers are both from the first week. Let's use the Least Common Multiple to make them equal while still keeping ratios.

LCM of 3 and 4: 12 = 3 * 4

12a : 8a ( times 4 )

12a : 15a ( times 3 )

Now that we have the same value, we can create a big ratio

first week second week third week

12a : 8a : 15a

we know that these ratios will all equal 385. Since ratios are equal no matter how big we make them, we can say that

12a + 8a + 15a = 385 (a is a variable to scale up the ratio)

which is the same as

(12 + 8 + 15) * a = 385

(35) * a = 385

35a = 385

if we solve for a by dividing 35 on both sides we get

a = 11

This gives us how much to multiply the RATIO by to get the ACTUAL NUMBER of orders completed. Let's plug 11 for 'a' and see what happens.

12a + 8a + 15a = 385

12(11) + 8(11) + 15(11) = 385

132 + 88 + 165 = 385 (Check that out, the number of orders each week!)

220 + 165 = 385

385 = 385

Bingo! All the math works out. So, looking back at the verryyy top of this problem, the reason why it wasn't as easy as $385 was because of the bonus.

The bonus gives David $1.25 per order instead of $1 per order if any of the weeks have an average ORDER PER DAY of anything bigger than 20. If we know the real numbers of orders for every week (132, 88, and 165), then we can divide it by 7 to get the average order per day. Let's choose 165 (the third week) because it is the biggest and has the greatest chance of meeting our goal.

165 orders / 7 days (7 days in a week) = 23.57 orders per day

Is this greater than 20 orders per day?

YES!

So now we can safely say that the bonus is there or not, and in this case, the bonus IS there because there is a week where David had more than 20 orders per day.

So instead of using

profit = $1x

We will use

bonus profit = $1.25x

(x is the amount of orders completed)

So if we know he completed 385 orders, and we know he earned the bonus, we plug in 385 for x for the bonus function

bonus profit = $1.25x

bonus profit = $1.25 * 385

bonus profit = $481.25

If necessary, round your answer to the nearest dollar.

So for the very end, all we have to do is round it to the nearest dollar.

$481.25 rounds to $481.

And we're done!

8 0

3 years ago

The gas co2 is diffusin at steady state through a tube 20 cm long having a diameter of 1 cm and containing n2 at 350 k . the tot

Marrrta [24]

The value is J = 1.71*10^-6 kmol/m^2.s

According to the given conditions we get,

The length the tube l= 0.20m

The diameter of the tube d= 0.01m

The total pressure inside the tube P= 101.32kPa

The partial pressure of CO2 at the first end is

P1= 456mm Hg = 60794.832 Pa

The partial pressure of CO2 at the other end is

P2= 76mm Hg = 10132.472 Pa

The temperature is T = 298 K

The diffusion coefficient D= 1.67* 10^-5 m^2/s

Generally the molar flux of CO2 is mathematically represented as

J= D{p1-p2} / R.T

Here R is the gas constant with value R= 8.314 j/kmol

So we get J= 1.71 * 10^-3 mol/m^2.sec

Learn more about Mole on:

brainly.com/question/27270616

#SPJ4

4 0

2 years ago

Based on a kc value of 0.210 and the data table given, what are the equilibrium concentrations of xy, x, and y, respectively?

a_sh-v [17]

The activation energy for the forward and the one for the reverse reaction are similar because they attained chemical equilibrium. A chemical equilibrium happens when both of the reactant and products achieve the same concentration.

4 0

3 years ago

A train traveled 63.75 miles at a rate of 85 miles per hour. Which equation can be used to find h, the number of hours it took t

sashaice [31]

Answer: 63.75 = 85h

Solving gives 0.75 hours.

Step-by-step explanation:

we now that speed = distance / time

therefore time will be Distance / speed

Given that distance = 63.75miles

Speed= 6=85miles per hour

Time(h) = 63.75miles/ 85.---- equation 1

But from the options given, the equation that can also be used to find number of hours is

63.75 = 85h

such that making h subject of formula still give us

h= 63.75/85 as in equation 1 above

solving gives that Time ( h) = 0.75 hours .

8 0

2 years ago

Is M a midpoint of line AB= ? AB= 27 and MB =14 A maybe B can’t be C no D yes

My name is Ann [436]

The answer is B/C.—M is in fact NOT a midpoint of line AB. This is because to be a midpoint the distance between both endpoints and the midpoint must me equal. If AB has equaled 28 then is would be, but in this case NO. To get AM you just need to do 27-14. AM would be 13 (if you need that too)

6 0

3 years ago