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3 years ago

Simplify (3x-21)/(7x-x²)with working pls

1 answer:

7 0

Okay so this is not too hard once you get the grasp of it. What you want to do is put everything with each other giving you the answer, -3x^2 +42x^2 -147x

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What is the midpoint between (-6,2) and (10,4)

mario62 [17]

Answer:

(2,3)

Step-by-step explanation:

To find the x-coordinate of the midpoint, find the average of -6 and 10. It is 4/2, or 2.

To find the y-coordinate, proceed similarly. Find the average of 2 and 4. It is 3.

Thus, the midpoint is (2, 3).

7 0

3 years ago

The square root of the quantity 4 x minus 3 end quantity equals 5.

zavuch27 [327]

Answer:

The statement is false.

Step-by-step explanation:

Given,

$\sqrt{4 \times - 3} = 5$

To Prove

Soln:

$\sqrt{4 \times - 3}$

= $2i \sqrt{3}$

=> $2i \sqrt{3} ≠5$

Hence, 2i√3 is not equal (≠) to 5.

3 0

2 years ago

Find the area of the circle whose equation is x2+y2=6x-8y

Semenov [28]

Answer:

Given that the equation of a circle is :

$\green{ \boxed{\boxed{\begin{array}{cc} {x}^{2} + {y}^{2} = 6x - 8y \\ = > {x}^{2} + {y}^{2} - 6x + 8y = 0 \\ = > {x}^{2} + {y}^{2} + 2 \times ( - 3) \times x + 2 \times 4 \times y = 0 \\ \\ \sf \: standard \: equation \: o f \: circle \: is : \\ {x}^{2} + {x}^{2} + 2gx + 2fy + c = 0 \\ \\ \sf \: by \: comparing \\ \\ g = - 3 \\ f = 4 \\ c = 0 \\ \\ \sf \: radius \: \: r = \sqrt{ {g}^{2} + {f}^{2} - c } \\ = \sqrt{ {( - 3)}^{2} + {4}^{2} - 0 } \\ = \sqrt{9 + 16} \\ = \sqrt{25} \\ = 5 \: unit \\ \\ \bf \: area \: = \pi {r}^{2} \\ = \pi \times {5}^{2} \\ =\pink{ 25\pi \: { unit }^{2} }\end{array}}}}$

6 0

3 years ago

A book is 0.33 meters long. How many millimeters long is it?

Phoenix [80]

we know that

$1\ meter=1,000\ millimeters$

by proportion

Find how many millimeters are in $0.33$ meters

$\frac{1,000}{1} \frac{mm}{m} =\frac{x}{0.33} \frac{mm}{m} \\ \\x=1,000*0.33 \\ \\ x=330\ mm$

therefore

<u>the answer is</u>

$330\ mm$

7 0

3 years ago

Each course at a community college is worth 1 or 2 credits. A group of students is taking a total of 16 courses that are worth a

Anuta_ua [19.1K]

Answer:

They are taking 12 2 credit courses

The are taking 4 1 credit courses

Step-by-step explanation:

x = 1 credit courses

y = 2 credit courses

The number of courses is 16

x+y = 16

The number of credits is 28 so multiply the course by the number of credits

1x+2y=28

Subtract the first equation from the second equation

x+2y =28

-x-y=-16

-----------------

y = 12

They are taking 12 2 credit courses

We still need to find the 1 credit courses

x+y = 16

x+12= 16

Subtract 12 from each side

x-12-12 = 16-12

x =4

The are taking 4 1 credit courses

6 0

3 years ago

Simplify (3x-21)/(7x-x²)with working pls​

Simplify (3x-21)/(7x-x²)with working pls