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geniusboy [140]
3 years ago
15

PLEASE HELP! MATHS QUESTION

Mathematics
1 answer:
Mariana [72]3 years ago
7 0
Density=8 g/cm^3
Divide it into two rectangles
Area of rectangle 1=7*2=14 cm^2
Area of rectangle 2=5*2=10 cm^2

Calculate volume of the two rectangle parts

Volume of rectangle 1=14*200=2800 cm^3
Volume of rectangle 2=10*200=2000 cm^3

Therefore volume of prism=4800 cm^3

Mass of prism=Density*Volume
=8*4800
=38400 g
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A random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample stand
Tpy6a [65]

Answer:

We conclude that the population mean is different from 10.5.

Step-by-step explanation:

We are given that a random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample standard deviation is 2.

<em>We have to test the claim that the population mean is 10.5.</em>

Let, NULL HYPOTHESIS, H_0 : \mu = 10.5  {means that the population mean is 10.5}

ALTERNATE HYPOTHESIS, H_a : \mu \neq 10.5  {means that the population mean is different from 10.5}

The test statistics that will be used here is One-sample t-test;

           T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean = 11

            s = sample standard deviation = 2

            \mu = population mean

            n = sample of values = 16

So, <u>test statistics</u> =  \frac{11-10.5}{\frac{2}{\sqrt{16} } } ~ t_1_5

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<em>Now, at 0.05 significance level, t table gives a critical value of 2.131 at 15 degree of freedom. Since our test statistics is way less than the critical value of t so we have insufficient evidence to reject null hypothesis as it will not fall in the rejection region.</em>

Therefore, we conclude that the population mean is different from 10.5.

6 0
4 years ago
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