The number of terms in the given arithmetic sequence is n = 10. Using the given first, last term, and the common difference of the arithmetic sequence, the required value is calculated.
<h3>What is the nth term of an arithmetic sequence?</h3>
The general form of the nth term of an arithmetic sequence is
an = a1 + (n - 1)d
Where,
a1 - first term
n - number of terms in the sequence
d - the common difference
<h3>Calculation:</h3>
The given sequence is an arithmetic sequence.
First term a1 =
= 3/2
Last term an =
= 5/2
Common difference d = 1/9
From the general formula,
an = a1 + (n - 1)d
On substituting,
5/2 = 3/2 + (n - 1)1/9
⇒ (n - 1)1/9 = 5/2 - 3/2
⇒ (n - 1)1/9 = 1
⇒ n - 1 = 9
⇒ n = 9 + 1
∴ n = 10
Thus, there are 10 terms in the given arithmetic sequence.
learn more about the arithmetic sequence here:
brainly.com/question/503167
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Disclaimer: The given question in the portal is incorrect. Here is the correct question.
Question: If the first and the last term of an arithmetic progression with a common difference are
,
and 1/9 respectively, how many terms has the sequence?
F(x)=5x+10
5x=-10
x=-10/5
x=-2
Result is f(-2).
Answer:
3 cm
Step-by-step explanation:
Area=length x width
6=length x 2
Length x 2=6
Length=6/2
Length=3
Using the factor theorem, it is found that the polynomial is:

Given by the first option
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Given a polynomial f(x), this polynomial has roots
using the factor theorem it can be written as:
, in which a is the leading coefficient.
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In this question:



- By the options, leading coefficient

Thus:



Which is the polynomial.
A similar problem is given that: brainly.com/question/4786502