M=dc/dp=4/6=4/6=2/3
c(p)=2p/3 +b using (6,4)
4=2(6)/3+b
4=4+b, b=0 so
c(p)=2p/3
(the number of cherries needed as a function of the number of pies)
There are two data sets x and y.
X includes = 14 25 19 35 20 12 5
Y includes = 360 293 315 212 315 331 404
to solve for the correlation coefficient, we need to get the following values step by step
Step 1: Find the mean of each set.
The mean of X = 18.571
The mean of Y = 318.571
Step 2: Subtract the mean of X from every value X value
(denote this with letter a). Do the same for y (denote this with letter b).
The mean of X subtracted from every X value (a):
14 - 18.571 = -4.571
25 - 18.571 = 6.429
19 - 18.571 = 0.429
35 - 18.571 = 16.429
20 - 18.571 = 1.429
12 - 18.571 = -6.571
5 - 18.571 = -13.571
The mean of Y subtracted from every value of Y (b):
360 - 318.571 = 41.429
293 - 318.571 = -25.571
315 - 318.571 = -3.571
212 = 318.571 = -106.571
315 - 318.571 = -3.571
331 - 318.571 = 12.429
404 - 318.571 = 85.429
Step 3: Calculate: a *
b, a^2 and b^2 of every value.
For a*b
-189.388
-164.388
-1.531
-1750.816
-5.102
-81.673
-1159.388
Sum: -3352.286
For a²
20.898
41.327
0.184
269.898
2.041
43.184
184.184
Sum: 561.714
For b²
1716.327
653.898
12.755
11357.469
12.755
154.469
7298.041
Sum: 21205.714
Step 4: Solve using this formula
r = ∑a * b / √((a²)(b²))
r = -3352.286 /
√((561.714)(21205.714))
= -0.9713
The correlation coefficient is -0.971
Answer:
y ≈ 16.33
Step-by-step explanation:
∆SPQ is a 30-60-90 right triangle
PS:QS:PQ = 1:2:√3
QS/PQ = 2/√3
QS/PQ = QS/10
QS/10 = 2/√3 Multiply each side by 10
QS = 20/√3
∆RSQ is a 45-45-90 right triangle.
∴ RS = QS = 20/√3
RS² + QS² = QR²
(20/√3)² + (20/√3)² = y²
400/3 + 400/3 = y²
800/3 = y² Take the square root of each side
y = √(800/3)
= 20√(2/3)
= (20√6)/3
≈ 16.33
Answer:
y = 2x - 4
Step-by-step explanation:
Rearrange the given equation to slope-intercept form.
x + 2y = 2
2y = -x + 2
y = -1/2x + 1
The slope of the given line is -1/2. The slope of a perpendicular line will be the negative inverse, meaning that the slope will be 2.
-1/2 = 2
Find the equation of the new line with the point-slope form using the new slope and given point.
y - y₁ = m(x - x₁)
y - 6 = 2(x - 5)
y - 6 = 2x - 10
y = 2x - 4
The equation will be y = 2x - 4.