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Leno4ka [110]
3 years ago
14

What's the Answer to this problem?

Mathematics
1 answer:
MariettaO [177]3 years ago
4 0
Depth = Volume / (length x width)
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Click on the graphic to select the figure that would make the following a reflection in line k
Roman55 [17]

I remember answering the same question, but you didn't attach any photos. But I remember that the answer is the first one.

I hope I helped. Stay safe and God bless!

- Eli <3

6 0
3 years ago
2. Solve: 33 + 2(5+8)-(6-2)
mars1129 [50]

Answer:

55

Step-by-step explanation:

Add the numbers 5 + 8 and you get 13. Multiply 13 x 2 which is 26. Add 33 + 26 and you get 59. Then, subtract it by 4 and you get 55.

6 0
3 years ago
For the given hypothesis test, determine the probability of a Type II error or the power, as specified. A hypothesis test is to
erica [24]

Answer:

the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

Step-by-step explanation:

Given the data in the question;

we know that a type 11 error occur when a null hypothesis is false and we fail to reject it.

as in it in the question;

obtained mean is 9.8 which is obviously not equal to 8.3

But still we fail to reject the null hypothesis says mean is 8.3

Hence we have to find the probability of type 11 error

given that; it is right tailed and o.5, it corresponds to 1.645

so

z is equal to 1.645

z = (x-μ)/\frac{S}{\sqrt{n} }

where our standard deviation s = 3.8

sample size n = 50

mean μ = 8.3

we substitute

1.645 = (x - 8.3)/\frac{3.8}{\sqrt{50} }

1.645 = (x - 8.3) / 0.5374

0.884023 = x - 8.3

x = 0.884023 + 8.3

x = 9.18402

so, by general rule we will fail to reject the null hypothesis when we will get the z value less than 1.645

As we reject the null hypothesis for right tailed test when the obtained test statistics is greater than the critical value

so, we will fail to reject the null hypothesis as long as we get the sample mean less than 9.18402

Now, for mean 9.8 and standard deviation 3.8 and sample size 50

Z =  (9.18402 - 9.8)/\frac{3.8}{\sqrt{50} }

Z = -0.61598 / 0.5374

Z = - 1.1462 ≈ - 1.15

from the z-score table;

P(z<-1.15) = 0.1251

Therefore, the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

8 0
3 years ago
What is 2,753 divided by 7?<br> Estimate the answer.
a_sh-v [17]
He answer is around 385 I believe??? Im not positive if thats what u wanted or not.
5 0
3 years ago
Read 2 more answers
Select the correct answer.
Andrej [43]

Answer:

C. y=4/5

Hope this helps

3 0
3 years ago
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