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nalin [4]
4 years ago
12

Which of the four answers is correct

Mathematics
1 answer:
Kipish [7]4 years ago
8 0

Answer:

A. 3√7/6 + √-3/5

Step-by-step explanation:

complex number: real number + imagine number   ( a + bi)

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What is the equation of the function that is graphed as line b?
Juli2301 [7.4K]

Following the slope of the line at x= 0 the line is at y =1 , at x=, it is at Y = 1.5, so the slope is 1/2

The y intercept is where the line crosses the y a is at x =0 which is 1

The equation would be y = 1/2x+ 1

5 0
3 years ago
A ball is dropped from a height of 192 inches onto a level floor. After the third bounce it is still 3 inches off the ground. Pr
ANEK [815]

Answer: The required fraction = \dfrac18

Step-by-step explanation:

Let the required fraction = \dfrac{p}{q}

Given: Initial height = 192 inches

Height of ball after second bounce = \dfrac{p}{q}\times192

Height of ball after third bounce = \dfrac{p}{q}\times\dfrac{p}{q}\times192=192\dfrac{p^2}{q^2}

After the third bounce it is 3 inches off the ground.

So,

(\dfrac{p}{q})^2192=3\\\\\\(\dfrac{p}{q})^2=\dfrac{3}{192}\\\\(\dfrac{p}{q})^2=\dfrac{1}{64}\\\\(\dfrac{p}{q})^2=(\dfrac{1}{8})^2\\\\ \dfrac{p}{q}=\dfrac{1}{8}

Hence, The required fraction = \dfrac18

5 0
3 years ago
12 days of math challenge​
erastova [34]

Answer:

Reindeer and snowflake are 4

tree is 8

snowman is 1

Step-by-step explanation:

8 0
3 years ago
A tank weighs 5.6kg when it 1/4 filled with water.If it weighs 10.4kg when it is full ,what will be it's weight when it is empty
Schach [20]

Answer:

4 kg

Step-by-step explanation:

so 1.6 * 4 is 6.4 so you just double check if you want

4 + 1.6 which is 1/4 of 6.4 will be 5.6 (matches with the question)

4 + (1.6*4) (indicates it's full) = 10.4( also Matches with the question)

there is another way by setting up an equation. let me know in comments if you want to see it that way

7 0
2 years ago
2*2=4-1=A<br> What does a equal
zmey [24]

Answer:

Step-by-step explanation: pemdas

4 divided by 4 - 1

1-1=0

a = 0

8 0
3 years ago
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