A tank weighs 5.6kg when it 1/4 filled with water.If it weighs 10.4kg when it is full ,what will be it's weight when it is empty
1 answer:
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15/18 - 2/18 = 13/18
Find the least common multiple of 6 and 9. The LCM is 18. In order to get 18 on the denominator with 6, you have to multiply by 3 because 6 times 3 is 18. You have to multiply 3 to the numerator, so 5 times 3 is 15. Thus, the first fraction is 15/18. To get the second, you need to find what would get you 18 on the denominator with 9. You need 2, so 9 times 2 is 18. You have to multiply 2 to the numerator, so 1 times 2 is 2. Thus, the second fraction is 2/18.
Find the least common multiple of 6 and 9. The LCM is 18. In order to get 18 on the denominator with 6, you have to multiply by 3 because 6 times 3 is 18. You have to multiply 3 to the numerator, so 5 times 3 is 15. Thus, the first fraction is 15/18. To get the second, you need to find what would get you 18 on the denominator with 9. You need 2, so 9 times 2 is 18. You have to multiply 2 to the numerator, so 1 times 2 is 2. Thus, the second fraction is 2/18.
Answer:
This situations represents the depth of the lake after t years.
The rate of decay is equal to 0.02 a year.
So the depth of the lake each year is 0.98 times the depth in the previous year.
It will take 5.77 years for the depth of the lake to reach 26.7 meters.
Step-by-step explanation:
Exponential equation of decay:
The exponential equation for the decay of an amount is given by:
In which D(0) is the initial amount and r is the decay rate, as a decimal.
A lake currently has a depth of 30 meters. As sediment builds up in the lake, its depth decreases by 2% per year.
This means that
So
This situation represents
The depth of the lake after t years.
The rate of growth or decay, r, is equal to
The rate of decay is equal to 0.02 a year.
So the depth of the lake each year is times the depth in the previous year.
1 - 0.02 = 0.9
So the depth of the lake each year is 0.98 times the depth in the previous year.
It will take between years for the depth of the lake to reach 26.7 meters.
This is t for which D(t) = 26.7. So
It will take 5.77 years for the depth of the lake to reach 26.7 meters.