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podryga [215]
3 years ago
15

Gina is driving her car down the street. She has a teddy bear sitting on the back seat. A dog runs in front of Gina's car, so sh

e quickly applies the brakes. The force of the brakes causes the car to stop, but the teddy bear continues to move forward until it hits the car's dashboard.
The teddy bear did not stop at the same time as the car because
Computers and Technology
2 answers:
kiruha [24]3 years ago
5 0
Newton's 1st Law of Motion- an object (bear) will stay in motion until acted upon by an unbalanced force
Nonamiya [84]3 years ago
3 0

Newton's first law of motion explains why the teddy bear in Gina's car did not stop at the same time as the car itself. The car was in motion until an external force caused the car to stop. The brakes did not act on the objects inside the car, they acted on only the car. The teddy bear, therefore, continued to stay in motion, even after the car had stopped. The teddy bear continued to move forward until it hit the dashboard of the car. The dashboard provided an outside force that stopped the motion of the teddy bear.

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Write a function that takes in two parallel lists: a list of times (in increasing order), and a list of distance traveled by tha
Georgia [21]

Below is the function that takes two parallel lists;

List of times in increasing order and that of distance travelled by that point in time.

I put into consideration the instructions given in the question.

ANSWER;

def find_velocity(time, distance):

velocities = []

for i in range(1, len(time)):

velocities.append((distance[i] - distance[i - 1]) / (time[i] - time[i - 1]))

return velocities

times are = [1, 3, 5, 7]

distances are = [25, 29, 35, 70]

print(find_velocity(times, distances))

7 0
3 years ago
Zach follows the instructions that show him how to create a custom Web site in his school's learning management system. These st
NNADVOKAT [17]

Answer:

The answer is "Procedure"

Explanation:

In the given statement certain information is missing, that is choices, which can be described as follows:

a. procedure

b. software

c. data

d. hardware

e. memory

The procedure is a way, that accomplishes any task in the following steps, if there is a long process so, we divide this process into parts or modules to accomplish the task, and  certain alternative was wrong, that can be described as  follows:

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Look at the logic program below. Set a breakpoint after each commented instruction. You can also single step through the program
Goshia [24]

Using programming knowledge, it is possible to use programming logic, we can differentiate and find the terms

<h3>Writing the code and understanding the programming logic:</h3>

<em>.data</em>

<em>sourceword:</em>

<em>.word 0xAB</em>

<em>wordmask:</em>

<em>.word 0xCF</em>

<em>operand:</em>

<em>.long 0xAA</em>

<em>.text</em>

<em>.globl _start</em>

<em>_start:</em>

<em>movw sourceword, %ax # ax=0x00AB ( move the word value of sourceword =0x00AB to ax register.)</em>

<em>movw %ax, %bx # bx=0x00AB ( copy the value of ax to bx register.)</em>

<em>xorw %cx, %cx # cx=0000 ( cx=cx XOR cx, that is clear cx register.)</em>

<em />

<em>andw wordmask, %ax # ax=0x008B ( ax=ax AND wordmask= 0x00AB AND 0x00CF= 0x008B)</em>

<em>orw wordmask, %bx # bx=0x00EF (bx=bx OR wordmask= 0x00AB OR 0x00CF= 0x00EF.)</em>

<em>xorw wordmask, %cx # cx=0x00CF (cx=cx XOR wordmask= 0x0000 XOR 0x00CF=0x00CF.)</em>

<em />

<em>movl operand, %eax # eax=0x000000AA. ( copy the 32-bit value of operand=0x000000AA to eax.)</em>

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<em>movl %eax, %ecx # ecx=0x000000AA. ( copy the value of eax to ecx.)</em>

<em />

<em>shll $3,%eax # eax=0x00000550. ( logical shift left of eax=0x000000AA by 3 bits.)</em>

<em />

<em># 0x000000AA=00000000000000000000000010101010</em>

<em />

<em># =>00000000000000000000010101010000=0x00000550.</em>

<em />

<em>rorl $4,%ebx # ebx=0xA000000A. (Rotate right ebx=0x000000AA by 4 bits.)</em>

<em />

<em># 0x000000AA=00000000000000000000000010101010</em>

<em />

<em>3 =>10100000000000000000000000001010= 0xA000000A.</em>

<em />

<em>sarl %ecx # here the count value to shift the bits not mentioned.</em>

<em />

<em># It is the arithmetic shift right instruction. the shifted left bits filled with MSB bit.</em>

See more about logic program at brainly.com/question/14970713

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Answer:A B

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Explanation:

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Answer:

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