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belka [17]
3 years ago
11

Simplify each expression. 6mn3 -mn2 + 3mn3 +15mn2??

Mathematics
1 answer:
bekas [8.4K]3 years ago
4 0

Answer:

9m(n)^3 +14m(n)^2

Step-by-step explanation:

6m(n)^3 - m(n)^2 + 3m(n)^3 + 15m(n)^2

=> 6m(n)^3 + 3m(n)^3 + 15m(n)^2 - m(n)^2

=> 9m(n)^3 +14m(n)^2

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Jamie is riding a Ferris wheel that takes fifteen seconds for each complete revolution. The diameter of the wheel is 10 meters a
Agata [3.3K]

Answer:

The answers to the question is

(a) Jamie is gaining altitude at 1.676 m/s

(b) Jamie rising most rapidly at t = 15 s

At a rate of 2.094 m/s.

Step-by-step explanation:

(a) The time to make one complete revolution = period T = 15 seconds

Here will be required to develop the periodic motion equation thus

One complete revolution = 2π,

therefore the  we have T = 2π/k = 15

Therefore k = 2π/15

The diameter = radius of the wheel = (diameter of wheel)/2 = 5

also we note that the center of the wheel is 6 m above ground

We write our equation in the form

y = 5*sin(\frac{2*\pi*t}{15} )+6

When Jamie is 9 meters above the ground and rising we have

9 = 5*sin(\frac{2*\pi*t}{15} )+6 or 3/5 = sin(\frac{2*\pi*t}{15} ) = 0.6

which gives sin⁻¹(0.6) = 0.643 =\frac{2*\pi*t}{15}

from where t = 1.536 s

Therefore Jamie is gaining altitude at

\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) = 1.676 m/s.

(b) Jamie is rising most rapidly when   the velocity curve is at the highest point, that is where the slope is zero

Therefore we differentiate the equation for the velocity again to get

\frac{d^2y}{dx^2} = -5*(\frac{\pi *2}{15} )^2*sin(\frac{2\pi t}{15}) =0, π, 2π

Therefore -sin(\frac{2\pi t}{15} ) = 0 whereby t = 0 or

\frac{2\pi t}{15} = π and t =  7.5 s, at 2·π t = 15 s

Plugging the value of t into the velocity equation we have

\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) = - 2/3π m/s which is decreasing

so we try at t = 15 s and we have \frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi *15}{15}) = \frac{2}{3} \pim/s

Hence Jamie is rising most rapidly at t = 15 s

The maximum rate of Jamie's rise is 2/3π m/s or 2.094 m/s.

7 0
3 years ago
Help 6th grade math please help i will give brainliest
lilavasa [31]

Answer:

multiply 12 times 9

Step-by-step explanation:

I'm pretty sure this is right, I'm sorry if it's wrong

3 0
2 years ago
The claim is that the proportion of drowning deaths of children attributable to beaches is more than 0.25, and the sample statis
Ainat [17]

Answer:

The test statistic Z = 3.125

Step-by-step explanation:

<em>Given Population proportion P = 0.25</em>

<em>Given sample size 'n' = 696</em>

<em>Sample proportion 'p⁻' = 0.30</em>

Test statistic

                 Z = \frac{p^{-}  -P}{\sqrt{\frac{P Q}{n} } }

                 Z = \frac{0.30-0.25}{\sqrt{\frac{0.25 X 0.75}{696} } }  = 3.125

<u><em>Final answer</em></u>:-

The test statistic Z = 3.125

3 0
3 years ago
What is the approximate distance between the points (-3, -4) and (-8, 1) on a coordinate grid
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4 0
2 years ago
Read 2 more answers
Find p(0),p(1),p(-1) and p(2) of the 3x(x-2) <br><br>​
Effectus [21]

Answer:

<u>make x→0</u>

p(0)=(0)^{2}-3(0)+2

→ p(0)=0+0+2

→p(0)=2

------

<u>Replace x→-1</u>

p(-1)=(-1) ^{2} -3 (-1)+2

→ p(-1)=1-3+2

→ p(-1)=0

----------

<u>Now make x→2</u>

p(2)=(2) ^{2} -3(2)+2

→ p(2)=4-6+2

→ p(2)=0

Answer:-2,0,0

-----------

hope it helps...

have a great day!!

5 0
3 years ago
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