The correct pair is a. Hope that helped!
H ( t ) = 15 - 10 t - 16 t² = - 16 t² - 10 t + 15
15 ft is the initial height, or H ( 0 ) and - 10 ft / s is the initial vertical velocity and 10ft/s is horizontal velocity. As for the time:
t 1/2 = (- b +/- √( b² - 4 a c ) )/ 2 a
t 1/2 = ( 10+/-√(100 + 960 ) ) / ( -32 ) =
= ( 10 - 32.56 ) / ( -32 ) = - 22.56 / ( - 32 ) = 0.705 s ( another solution is negative )
d = vo x · t = 10 ft/s · 0.705 s = 7.05 ft.
Answer: She will land 7.05 ft from the base of the overhang.
Answer:
<u>Is "y (x-4) squared +6": y = (x-4)^2 + 6?</u>
If so,
<u>x = y^(1/2) - 6^(1/2) + 4</u>
Step-by-step explanation:
<h2><u>
Assuming the equation is: y= (x-4)^2 + 6</u></h2>
y^(1/2)= (x-4) + 6^(1/2)
(x-4) = y^(1/2) - 6^(1/2)
x = y^(1/2) - 6^(1/2) + 4
I may be wrong but I think it’s Monica
Answer:
It says that for me too, there must be a problem with their system.
Try asking the specific problem you are having, so if someone had that specific problem before, they can walk you through it! :)