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Mice21 [21]
4 years ago
9

A line passes through (4, 5) and (8, 9). Which equation best represents the line?

Mathematics
2 answers:
kramer4 years ago
5 0
The correct answer is y= x+1

kodGreya [7K]4 years ago
3 0

Answer:

The answer is A, y = x + 1

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How many sides does a regular polygon have if it’s central angle is 35 degrees?
umka21 [38]

Answer:

it's not a regular polygon

Step-by-step explanation:

a central angle of a regular polygon is 360/n

360/n=35

n=360/35=10.28

it's not a regular polygon

8 0
3 years ago
Heklp me again please if you dont mind
matrenka [14]

Step-by-step explanation:

This is the answer of this question.

4 0
3 years ago
A bottle of root beer contains 4/5 L. How much root beer is in 3 bottles?
shusha [124]
3\cdot\frac{4}{5}=2.4 \hbox{ l}
5 0
4 years ago
If f(x)=x+7 and g(x)= 1 divided by x-13, what is the domain of (f•g)(x)?
andrew11 [14]
<h2>Hello!</h2>

The answer is:

The domain of the function is all the real numbers except the number 13:

Domain: (-∞,13)∪(13,∞)

<h2>Why?</h2>

This is a composite function problem. To solve it, we need to remember how to composite a function. Composing a function consists of evaluating a function into another function.

Composite function is equal to:

f(g(x))=(f\circ} g)(x)

So, the given functions are:

f(x)=x+7\\\\g(x)=\frac{1}{x-13}

Then, composing the functions, we have:

f(g(x))=\frac{1}{x-13}+7\\

Therefore, we must remember that the domain are all those possible inputs where the function can exists, most of the functions can exists along the real numbers with no rectrictions, however, for this case, there is a restriction that must be applied to the resultant composite function.

If we evaluate "x" equal to 13, the denominator will tend to 0, and create an indetermination since there is no result in the real numbers for a real number divided by 0.

So, the domain of the function is all the real numbers except the number 13:

Domain: (-∞,13)∪(13,∞)

Have a nice day!

5 0
3 years ago
A line has a slope of -2/5 and passes through the point (10,7) . Write the equation of this line in point-slope form, slope-inte
qaws [65]

(\stackrel{x_1}{10}~,~\stackrel{y_1}{7})\hspace{10em} \stackrel{slope}{m} ~=~ -\cfrac{2}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7}=\stackrel{m}{-\cfrac{2}{5}}(x-\stackrel{x_1}{10})

6 0
1 year ago
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