You said that (xy) = 16, and (x+y) = 4 .
From the second equation you can get [ x = 4 - y ],
then substitude that for 'x' in the first equation, and
finally, rearrange the first equation to read
<u>x² - 4x + 16 = 0</u>
Don't even try to factor that quadratic equation. Go straight
to the quadratic formula, and the two solutions you find are ...
<em>x = 2 + i 2√3</em>
and
<em>x = 2 - i 2√3</em> .
Those are the two number that do what you want.
There are no <u>real</u> numbers that can do it.
Step 1: plug in the numbers. 7(6)-4
Step 2 multiply 7x6 42-4
Answer:
<h2>W = 16</h2>
Step-by-step explanation:
<h3>
![\sqrt[4]{W} = 2](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7BW%7D%20%20%3D%202)
</h3>
To find W raise each of the sides of the equation to the power 4 to make W stand alone
That's
<h3>
![( { \sqrt[4]{W} })^{4} = {2}^{4}](https://tex.z-dn.net/?f=%28%20%7B%20%5Csqrt%5B4%5D%7BW%7D%20%7D%29%5E%7B4%7D%20%20%3D%20%20%7B2%7D%5E%7B4%7D%20)
</h3>
We have
W = 2⁴
We have the final answer as
<h3>W = 16</h3>
Hope this helps you
Answer:
10 candy bars
Step-by-step explanation:
Since each of his friends needs a candy bar, you need to multiply 6 and 1 ⅔ together.
First, convert 1 ⅔ into an improper fraction: this gives us ⁵⁄₃.
Next, multiply ⁶⁄₁ and ⁵⁄₃ together. To do this, you can visualize 6 as ⁶⁄₁ (which is the same thing). Now you have ⁶⁄₁ x ⁵⁄₃.
<u>Simplify:</u>
The 6 in the numerator and the 3 in the denominator cancel out. This gives us ²⁄₁ x ⁵⁄₁ , which is 2 x 5.
2 x 5 = 10
