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2 years ago

Write a/-b in standard form

Mathematics

1 answer:

iogann1982 [59]2 years ago

7 0

Answer:

In order to write it in standard form, you need an equal sign somewhere

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In a year group there 100 boys and 140 girls. Write as a ratio the number of boy to the number of girls. Give the answer in the

expeople1 [14]

no. of boys : no.of girls

100 : 140

to get the simplest ratio you gotta divide both with a common factor

Because both 100 and 140 share a common factor of 20

the simplest ratio will be

100/20 : 140/20

5:7

5:7 is the simplest ratio

5 0

3 years ago

Read 2 more answers

Find the midpoint of the line segment with the given endpoints<br> (4,-6), (9, 6)

kotegsom [21]

Answer:

I think it's number 5 or (5,8)

Step-by-step explanation:

4 0

2 years ago

Help me on this one please

shepuryov [24]

Answer:

The equation is set up wrong

Step-by-step explanation:

$9^{2} +b^{2} =15^{2}$

3 0

3 years ago

Integrate the following

enot [183]

I suppose you mean to have the entire numerator under the square root?

$\displaystyle\int_2^4\frac{\sqrt{x^2-4}}{x^2}\,\mathrm dx$

We can use a trigonometric substitution to start:

$x=2\sec t\implies\mathrm dx=2\sec t\tan t\,\mathrm dt$

Then for $x=2$ , $t=\sec^{-1}1=0$ ; for $x=4$ , $t=\sec^{-1}2=\frac\pi3$ . So the integral is equivalent to

$\displaystyle\int_0^{\pi/3}\frac{\sqrt{(2\sec t)^2-4}}{(2\sec t)^2}(2\sec t\tan t)\,\mathrm dt=\int_0^{\pi/3}\frac{\tan^2t}{\sec t}\,\mathrm dt$

We can write

$\dfrac{\tan^2t}{\sec t}=\dfrac{\frac{\sin^2t}{\cos^2t}}{\frac1{\cos t}}=\dfrac{\sin^2t}{\cos t}=\dfrac{1-\cos^2t}{\cos t}=\sec t-\cos t$

so the integral becomes

$\displaystyle\int_0^{\pi/3}(\sec t-\cos t)\,\mathrm dt=\boxed{\ln(2+\sqrt3)-\frac{\sqrt3}2}$

7 0

3 years ago

Review of the basic stock list for your gift shop indicates that you need to reorder the following items: 12 glass vases @ $8.75

Aloiza [94]

Answer:

$291.00

hope it helps

Step-by-step explanation:

12 x 8.75 = 105

6 x 12.50 = 75

12 x 9.25 = 111

105 + 75 + 11 = 291

5 0

3 years ago

Read 2 more answers