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shtirl [24]
3 years ago
9

The area of a rectangular city park is 25/54 square miles. The length of the park is 5/9 mile. What is th width, in miles, of th

e park?
Mathematics
1 answer:
wolverine [178]3 years ago
7 0

Answer:

0.833 miles

Step-by-step explanation:

Because you know the area, you can use the formula for area of a rectangle. Just plug in what you know and solve.

\frac{25}{54} = \frac{30}{54}w

30/54 is the same as 5/9.

(\frac{25}{54})54 = (\frac{30}{54}w)54

Multiply by its denominator.

25=30w

Simplify

25/30=30w/30

Divide by 30

w=\frac{5}{6}

5/6 is roughly 0.833

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Maria comprou 21 metros de corda. Depois comprou 33 metros do mesmo tipo de corda, pagando R$ 9,60 a mais do que pagou na primei
Damm [24]

Vamos calcular quantos metros de corda Maria comprou na segunda vez:

33 - 21 = 12


Ela pagou R$ 9,60 a mais na segunda compra do que na primeira.


Logo, Maria pagou R$ 9,60 em 12 metros


Agora vamos calcular quanto ela pagou por metro:

9,60 ÷ 12 = 0,80


R$ 0,80 por metro


Para saber quanto Maria gastou na primeira compra multiplicamos os 21 metros pelo seu valor unitário:

21 × 0,8 = 16,80


Resposta: R$ 16,80 Letra B



4 0
3 years ago
Read 2 more answers
20 POINTS QUESTION IN PICTURE
Serga [27]
Domain includes all the x-values in the function. Range includes all the y-values in the function.

The first table has x-values of -1, 3, and 6, and y-values of 4, 5, and 6. This means that the domain and range would be given by the following sets:
Domain: {-1, 3, 6}
Range: {4, 5, 6}

The second set of points has x-values of -4, -4, -3, and 1, and y-values of 1, 1, 3, and 4. Duplicate points are not listed within the domain and range, so the domain and range would be given by the following sets:
Domain: {-4, -3, 1}
Range: {1, 3, 4}
7 0
3 years ago
Read 2 more answers
I need help understanding these it’s my school work
cestrela7 [59]

Answer:

I believe that

1) Isosceles, acute

3) Scalene, obtuse

5) Isosceles, right

7) Equilateral, acute

Step-by-step explanation:

This should help in the future. :)

4 0
3 years ago
Find the product using suitable identities.<br> a) <img src="https://tex.z-dn.net/?f=%28%5Cfrac%7Bx%7D%7B3%7D%20%20-%206%29%5E%7
Vesna [10]

Answer:

\frac{x^2}{9} - 4x + 36

Step-by-step explanation:

(\frac{x}{3} - 6)² = (\frac{x}{3} - 6)(\frac{x}{3} - 6)

Each term in the second factor is multiplied by each term in the firs t factor, that is

\frac{x}{3}(\frac{x}{3} - 6) - 6(\frac{x}{3} - 6)

Distribute both parenthesis

= \frac{x^2}{9} - 2x - 2x + 36 ← collect like terms

= \frac{x^2}{9} - 4x + 36

5 0
3 years ago
D is between C and E, CD = x 2 , CE = 32-2x, and DE = 12x. Find CD, DE, and CE.
Gemiola [76]

Answer:

  • CD = 4
  • DE = 24
  • CE = 28

Step-by-step explanation:

The segment addition theorem tells you ...

  CD +DE = CE

  x^2 +12x = 32 -2x

Subtract the right side to put this in standard form.

  x^2 +14x -32 = 0

  (x +16)(x -2) = 0

  x = -16 or 2

In order for DE to have a positive length, we must have x > 0. So ...

  CD = x^2 = 2^2 = 4

  DE = 12x = 12(2) = 24

  CE = 32 -2x = 32 -2(2) = 28

3 0
3 years ago
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