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valentinak56 [21]
4 years ago
15

A wall that is 10 feet high and 20 feet long contains one ton of bricks. How many tons should be purchased to brick a wall that

measures 1,800 square feet?
Mathematics
2 answers:
vitfil [10]4 years ago
7 0

Answer:

9 tons

Step-by-step explanation:

So first we have to figure out the area of the smaller wall. We know it is 10 feet high and 20 feet long, so we multiply the length and width together to get 200 square feet, and that equals 1 ton. Now if we take the 1800 square foot wall and divide it by the smaller wall, we get 9. This is because the larger wall is 9 times the size of the smaller wall. So if the smaller wall needs 1 ton, and the larger would need 9 times the amount, we would need 9 tons.

uranmaximum [27]4 years ago
7 0

Answer:

9 tons = 1800ft^2  (Area wall)

Step-by-step explanation:

1800 is 9 x larger than a smaller 10 x 20 = 200ft^2 Area

So we know this is 9 tons.

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R is the midpoint of QS, if QR=2x and RS=x+3, what is RS?
lbvjy [14]
Q -------------R------------S

suppose this is your line,

R is the mid point

and it's given that

QR = 2x
and
RS = x+3

as R is the mid point of QS
so,
QR = RS
then,
2x = x + 3
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as,
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5 0
3 years ago
I need help fast pleasee
trapecia [35]

Answer:

<em>y = - cos ( </em>\frac{3}{4}<em> x + </em>\frac{\pi }{4}<em> ) </em>

Step-by-step explanation:

y = A cos ( Bx + C) + D

Vertical shift D = 0

A = - 1

Compression / Stretching B

Period of given function is \frac{8\pi }{3}

Period of cos x is 2π

\frac{8\pi }{3} = \frac{2\pi }{B} ⇒ B = \frac{3}{4}

Horizontal shift is C ÷ B

Horizontal shift of given function is \frac{\pi }{3}

\frac{\pi }{3} = C ÷ \frac{3}{4} ⇒ C = \frac{\pi }{4}

So, the equation of given function is

<em>y = - cos ( </em>\frac{3}{4}<em> x + </em>\frac{\pi }{4}<em> ) </em>

4 0
2 years ago
Javier volunteers in community events each month. He does not do more than five events in a month. He attends exactly five event
mezya [45]

Answer:

The probability of Javier volunteers for less than three a month is 25%

Step-by-step explanation:

According to the questions,

The probability of Javier to attend exactly 5 events :-

P ( x = 5 ) = 25% = \frac{1}{4}

The probability of Javier to attend exactly 4 events :-

P ( x = 4 ) = \frac{1}{4}

The probability of Javier to attend exactly 3 events :-

P ( x = 3 ) = \frac{1}{4}

The probability of Javier to attend exactly 2 events :-

P ( x = 2 ) = \frac{3}{20}

The probability of Javier to attend exactly 1 events :-

P ( x = 1 ) = \frac{1}{20}

The probability of Javier to attend no events :-

P ( x = 0 ) = \frac{1}{20}

Now we have to calculate the probability of Javier volunteers for less than three P ( x < 3 ).

P ( x < 3 ) = P ( x = 0 ) + P ( x = 1 ) + P ( x = 2 )

P ( x < 3 ) = \frac{1}{20} + \frac{1}{20} + \frac{3}{20}   = \frac{1 + 1 + 3}{20}  = \frac{5}{20}  = \frac{1}{4}   = 0.25 = 25 %.

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3 0
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