There are 4 aces in a deck of 52 cards. the odds of drawing one is 1/13. the probability of doing it again is still 1/13. the odds of doing it twice, as described, is then 1/13 * 1/13, or (1/13)², or 1/169 option A
Answer:
AC=18
Step-by-step explanation:
To find AC, use the Pythagorean Theorem. Since the longest side (hypotenuse) is known, instead of a²+b²=c², the equation will be c²-a²=b². 12²-8²=b²
144-64=b²
80=b²
√80=√b²
8.94427191=b
That is for one of the two right triangles that make up the tent. Since there are 2 triangles, 8.94427191 only equals BC or AB. So, multiply 8.94427191×2=17.88854382 to find the length of AC.
AC= 18
Joshua pays 43.78 because he buys 22 packs. I found this by 110/5 . Then I multiplied 1.99 by 22 and got the final answer $43.78
12 x 6s - 8 x 4s = 72s - 32s = 40s

The rows add up to

, respectively. (Notice they're all powers of 2)
The sum of the numbers in row

is

.
The last problem can be solved with the binomial theorem, but I'll assume you don't take that for granted. You can prove this claim by induction. When

,

so the base case holds. Assume the claim holds for

, so that

Use this to show that it holds for

.



Notice that






So you can write the expansion for

as

and since

, you have

and so the claim holds for

, thus proving the claim overall that

Setting

gives

which agrees with the result obtained for part (c).