We can solve this problem by referring to the standard
probability distribution tables for z.
We are required to find for the number of samples given the
proportion (P = 5% = 0.05) and confidence level of 95%. This would give a value
of z equivalent to:
z = 1.96
Since the problem states that it should be within the true
proportion then p = 0.5
Now we can find for the sample size using the formula:
n = (z^2) p q /E^2
where,
<span> p = 0.5</span>
q = 1 – p = 0.5
E = estimate of 5% = 0.05
Substituting:
n = (1.96^2) 0.5 * 0.5 / 0.05^2
n = 384.16
<span>Around 385students are required.</span>
Answer:
726
Step-by-step explanation:
Here p = k / q², and 24 = k / 121, or k = 2904
Then p = 2904 / q²
If q = 2, p = 2904 /4 = 726
3 rows of 12
9 rows of 4
2 rows of 18
6 rows of 6
Answer:
To solve the above problem we will use the unitary method as follows
As estimated If £ 3 is equivalent to € 4
Then, £ 1 will be equivalent to = € \frac{4}{3}
£ 64.60 will be equivalent to = € \frac{4}{3} \times 64.60 = 1.3333 \times 64.60 = 86.1311
Now you have to round the answer up to 2 decimal points to get the final answer
€ 86.1311 ≈ € 86.13
Thus, £ 64.60 is approximately equal to € 86.13.
Step-by-step explanation:
hope this helps if not let me now
