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professor190 [17]
3 years ago
6

4. Consider the function f(x)=x^2-4

Mathematics
1 answer:
Olin [163]3 years ago
5 0

Answer:

B write a function that

shift f(x)right 8 units.

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Vertex of x^2-10x+30
Shtirlitz [24]

The easiest way to find the vertex is to convert this standard form equation into vertex form, which is y = a(x - h)^2 + k.

Firstly, put x^2 - 10x into parentheses: y = (x^2 - 10x) + 30

Next, we want to make what's inside the parentheses a perfect square. To do that, we need to divide the x coefficient by 2 and square it. In this case, the result is 25. Add 25 inside the parentheses and subtract 25 outside of the parentheses: y = (x^2 - 10x + 25) + 30 - 25

Next, factor what's inside the parentheses and combine like terms outside of the parentheses, and your vertex form is: y = (x - 5)^2 + 5.

Now going back to the formula of the vertex form, y = a(x - h)^2 + k, the vertex is (h,k). Using our vertex equation, we can see that the vertex is (5,5).

3 0
3 years ago
Read 2 more answers
Determine whether the sets have a subset relationship. R = {right triangles} O = {obtuse triangles} a) R and O are disjoint. b)
DerKrebs [107]

Answer:

f

Step-by-step explanation:

A right angled triangle has one angle equal to 90°

an obtuse angle triangle has one angle greater tan 90°

a) An o and right-angled triangle btuse angled triangle can have one angle equal.

b) R and O are not equivalent by definition

c)  subset of R and Oare not all triangles as R and O are categories of all triangles. R and O are subset of all triangles

d) Acute triangles have all acute angles. So subset of R and O can't be all acute traingles

e) All triangles with two acute angles are may or may not have third angle as obtuse angle or 90° angle

f) none of the above

5 0
3 years ago
What is the value of k in the equation k\3 -5=34
Alex
If wrong i apologize but for that equation i got the answer K=117
4 0
3 years ago
Read 2 more answers
A triangle has side lengths of 10, 20, and 30. what type of triangle is it
Alexeev081 [22]
Right triangle bc a^2+b^2=c^2. (Pythagorean theorem)
4 0
3 years ago
A model car travels around a circular track with radius 5 feet. Let Z denote the distance between the model car and a fixed poin
Eddi Din [679]

Answer:

\frac{dZ}{dt}= \frac{40}{\sqrt{545} } , so the model car is moving away from the fixed point at a rate of approximately 1.7 feet per second.

Step-by-step explanation:

The functions x and y satisfy (x−20)^2+y^2=25 and differentiating gives 2(x−20)dx/dt+2y dy/dt=0. Substituting the three known values and solving for dy/dt yields dy/dt=−32. Since Z=x^2+y^2−−−−−−√, dZ/dt=(2x ^ dx/dt+2y^dy/dt) / 2x2+y2√. Substituting Since Substituting for x, y,\frac{dx}{dt} , and \frac{dy}{dt} gives \frac{dZ}{dt}= \frac{40}{\sqrt{545} } ,

5 0
3 years ago
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