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3 years ago

20)

Mathematics

1 answer:

Natali5045456 [20]3 years ago

7 0

Answer:

The correct option is A) The growth factor of the investment.

Step-by-step explanation:

Consider the provided exponential function.

$V(t) = 30,000(1.125)^t$

Where V(t) is the total value after t years.

Here the function is in the form of Exponential Growth:

$y = a(b)^x$

Where b value is the growth factor.

By comparing we get that the constant '1.125' represents the growth factor by which our value is increasing each year.

Constant '30,000' represents the initial value i.e. the investment made.

Hence, the correct option is A) The growth factor of the investment.

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“Peaches at the Farmer’s Market cost $2.70 per pound.”

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Answer:

non-proportional

Step-by-step explanation:

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3 years ago

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What two partial products would you add to find 513 x 46

Afina-wow [57]

First, let me do the Mathematical part of that, and then I shall explain the theory behind it.

Mathematical part:
We are going to multiply 513 with 46. So the two partial products that we are going to choose are 40 and 6.

Multiply 513 with 6 first.

  513
x46
--------------------------
  18 (as 6*3 = 18)
  60 (as 6*10 = 60; In 513, the digit at tenths place is 1, so 1*10=10)
  3000 (as 6*500 = 3000; In 513, 5 is at hundredth place, so 5*100=500)
  120 (as 40*3 = 120; since 4 is at the tenth place, so 4*10=40)
  400 (as 40*10 = 400)
20000 (as 40*500 = 20000)
--------------------------
23598 (Add all of them)

Theory:
As you can see above that we have chosen the two partial products individually which are 6 and 40. Since 4 in 46 is in tenth place, we have to consider it 40 (since 4*10 = 40). One by one, we first multiply 6 with 513. Then we move to the tenth place, and multiply 513 with 40. At the end, we have added all the results we found after multiplication.

Check: If we check the multiplication result by using the calculator, we would get the same result (23598).

Another Method (instant):
513 * (40+6) = (513*40) + (513*6) = 23598.

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3 years ago

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The Versatech Corporation has decided to produce three new products. Five branch plants now have excess production capacity. The

RSB [31]

Answer: provided in the explanation segment

Step-by-step explanation:

here i will give a step by step analysis of the question;

A: Optimization Formulation

given Xij = X no. of units of product i manufactured in Plant j, where i = 1,2,3 and J = 1,2,3,4,5

Objective function: Minimize manufacturing cost (Z)

Z = 31 X11 + 29 X12 + 32X13 + 28X14 + 29 X15 + 45 X21 + 41 X22 + 46X23 + 42X24 + 43 X25 + 38 X31 + 35 X32 + 40X33

s.t

X11 + X12 + X13 + X14 + X15 = 600

X21 + X22 + X23 + X24 + X25 = 1000

X31 + X32 + X33 = 800

X11 + X21 + X31 <= 400

X12 + X22 + X32 <= 600

X13 + X23 + X33 <= 400

X14 + X24 <= 600

X15 + X25 <= 1000

Xij >= 0 for all i,j

Yes, we can formulate this problem as a transportation problem because in transportation problem we need to match the supply of source to demand of destination. Here we can assume that the supply of source is nothing but the manufacturing capability of plant and demand of destination is similar to the demand of products.

cheers i hope this helps!!