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iren [92.7K]
2 years ago
10

A movie club charges a one-time membership fee of $25. It allows members to purchase movies for $7 each. Another club does not c

harge a membership fee and sells movies for $12 each. How many movies must a member purchase for the total cost of the two clubs to be equal?
Mathematics
2 answers:
sashaice [31]2 years ago
7 0

Answer: $$5$$ movies

Step-by-step explanation: Given: A movie club, one time fee

=

$

25

, movies

=

$

7

       

2nd club,

$

0

fee, movies

=

$

12

Cost equations for each club:

club 1:

C

1

=

25

+

7

M

club 2:

C

2

=

12

M

For the clubs cost to be equal:

C

1

=

C

2

25

+

7

M

=

12

M

Subtract

7

M

from both sides:

25

=

5

M

Divide by

5

:

M

=

25

5

=

5

5

movies

CHECK:

C

1

=

25

+

7

⋅

5

=

25

+

35

=

$

60

C

2

=

12

⋅

5

=

$

60

Free_Kalibri [48]2 years ago
4 0

Answer:

5 movies

Step-by-step explanation:

<u>Define the variables:</u>

  • x = number of movies purchased
  • y = total cost

Create two equations from the given information.

<u>Equation 1</u>

Given:

  • A movie club charges a one-time membership fee of $25.
  • It allows members to purchase movies for $7 each.

⇒ y = 25 + 7x

<u>Equation 2</u>

Given:

  • Another club does not charge a membership fee.
  • It sells movies for $12 each.

⇒ y = 12x

To find how many movies a member must purchase for the total cost of the two clubs to be equal, <u>substitute</u> Equation 2 into Equation 1 and solve for x:

⇒ 12x = 25 + 7x

⇒ 12x - 7x = 25 + 7x - 7x

⇒ 5x = 25

⇒ 5x ÷ 5 = 25 ÷ 5

⇒ x = 5

Therefore, a member must purchase 5 movies for the total cost of the two clubs to be <u>equal</u>.

Learn more about systems of equations here:

brainly.com/question/27034625

brainly.com/question/27868564

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Answer:

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Answer:

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The hypotenuse of the right angle triangle  = 20cm

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    x = 4 + 12

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