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nikdorinn [45]
2 years ago
13

Need help please. I suck at math and these two are hard

Mathematics
1 answer:
Digiron [165]2 years ago
6 0
#11
The steepest slope would be m=5
This is the same as 5/1 so you are going UP 5 units for every one unit movement right.
#12
y=mx+b
The b is where it crosses the y axis. This is -2.
The slope is negative because it FALLS from left to right.
Rise/run is 2/7 so slope is -2/7
y = -2/7x -2
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Want money. Answer this.
elena-14-01-66 [18.8K]

Answer:

lol

Step-by-step explanation:

nothiing

6 0
3 years ago
Read 2 more answers
Lin solved the equation
Alekssandra [29.7K]

Answer: x=1/2

she was wrong, it's supposed to be

Step-by-step explanation: 8(x−3)+7=2x(4−17)

Step 1: Simplify both sides of the equation.

8(x−3)+7=2x(4−17)

(8)(x)+(8)(−3)+7=2x(4−17)(Distribute)

8x+−24+7=−26x

(8x)+(−24+7)=−26x(Combine Like Terms)

8x+−17=−26x

8x−17=−26x

Step 2: Add 26x to both sides.

8x−17+26x=−26x+26x

34x−17=0

Step 3: Add 17 to both sides.

34x−17+17=0+17

34x=17

Step 4: Divide both sides by 34.

34x/34=17/34 x=1/2

3 0
2 years ago
At a school pep rally the ratio of students who wore red to those who wore yellow is 7 to 3 their are 300 students at the rally
Serhud [2]
Red to yellow.......7:3....added = 10
so 7/10 of the total students wore red and 3/10 of the total students wore yellow

and there are 300 total students...
7/10(300) = 2100/10 = 210 wore red
3/10(300) = 900/10 = 90 wore yellow

how many more wore red.....(210 - 90) = 120 more students wore red then yellow
5 0
3 years ago
The fitness center held a weight loss competition in which 128 people participated. The amount of weight loss was normally distr
iris [78.8K]

Answer:

37

Step-by-step explanation:

Given :

Sample size, n = 128

Mean, μ = 18

Standard deviation, σ = 5.4

Number of people who lost atleast 15 pounds :

The Zscore = (x - μ) / (σ)

Zscore = (15 - 18) / 5.4

Zscore = - 3 / 5.4

Zscore = - 0.5555

P(Z < - 0.555) = 0.28945

Number of people who lost atleast 15 pounds :

0.28945 * 128 = 37.0496

= 37 people

3 0
3 years ago
State the horizontal asymptote of the rational function. For full credit, explain the reasoning you used to find the horizontal
Rzqust [24]

So here are the rules of horizontal asymptotes:

  • Degree of Numerator > Degree of Denominator: No horizontal asymptote
  • Degree of Numerator = Degree of Denominator: y=\frac{\textsf{leading coefficient of numerator}}{\textsf{leading coefficient of denominator}}
  • Degree of Numerator < Degree of Denominator: y = 0

Looking at the rational function, since the degree of the numerator is 2 and the degree of the denominator is 1 (and 2 > 1), this means that <u>this function has no horizontal asymptote.</u>

5 0
3 years ago
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