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3 years ago

What is the value of |-2/3|?

Mathematics

2 answers:

solong [7]3 years ago

5 0

Answer:

If the question is:

|-2÷3|, the answer is 0.6 repeating

|-2|, the answer is 2

|3|, the answer is 3

Step-by-step explanation:

With |(number)|, it wants you to find the absolute value.

The absolute value is the distance between a number and zero. The absolute value of a number is always positive.

Sergio [31]3 years ago

4 0

Answer:

Step-by-step explanation:

| | Makes any negative value positive

|-2/3| = 2/3

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A farmer plans crops on 48 acres of land. The circle graph shows the percentages of land used for some of the different types of

Alborosie

Answer:

14.4 acres for corn (if you need to round, it's 14 acres.)

Step-by-step explanation:

40% = 19.2 acres

20% = 9.6 acres

10% = 4.8 acres

40 + 20 + 10 = 70

100-70 = 30

30% = 14.4 acres

5 0

3 years ago

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What is the slope of a line parallel to 5x-3y=-10

Llana [10]

For parallel lines, slopes are equal.
5x - 3y = -10
3y = 5x + 10
y = 5/3 x + 10/3

Required slope = 5/3

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2 years ago

A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the

Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

$\pi r^2 h=25$

$\Rightarrow h=\frac{25}{\pi r^2}$

The surface area of the base of the can is = $\pi r^2$

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× $2\pi rh$ )

$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

Putting $h=\frac{25}{\pi r^2}$

$\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}$

$\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}$

Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

$C''=4\pi + \frac{125}{ r^3}$

To find the minimize cost, we set C'=0

$4\pi r- \frac{62.5}{ r^2}=0$

$\Rightarrow 4\pi r=\frac{62.5}{ r^2}$

$\Rightarrow r^3=\frac{62.5}{ 4\pi}$

⇒r=1.71

Now,

$\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=\frac{25}{\pi\times 1.71^2}$

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Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

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3 years ago

Dvinal [7]

Answer B

Explanation: Y=mx+b
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3 years ago

Mrs Ruiz needs to put 0.25 oz of water into each cup for a science experiment. How many cups can she fill with a 24 oz bottle of

balu736 [363]

She can fill 96 cups because you divide 24 by .25

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3 years ago

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