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Morgarella [4.7K]
3 years ago
5

Find the volume of the cone. Use 3.14 for π. Round to the nearest tenth.

Mathematics
1 answer:
Leviafan [203]3 years ago
6 0

Volume\,\,of\,\,cone=1527.1\,\,cm^3

So, Option C is correct.

Step-by-step explanation:

We need to find Volume of cone.

We are given:

π = 3.14

Length = 27 cm

Diameter = 15 cm

The formula used to find Volume of cone is:

Volume\,\,of\,\,cone=\frac{1}{3}\pi  r^2h

We are given diameter but we need radius in the formula

So, Radius = Diameter/2 = 15/2 = 7.5 cm

We need to find height of cone.

Using Pythagoras theorem:

h^2=p^2+b^2\\ (27)^2=p^2+(7.5)^2\\729=p^2+56.25\\p^2=729-56.25\\p^2=672.75\\Taking\,\,square\,\,root:\\p=25.93

So, Height of cone = p= 25.93

So, r= 7.5 and h= 25.93 and π = 3.14

Putting values in the formula:

Volume\,\,of\,\,cone=\frac{1}{3}3.14*(7.5)^2*25.93

Volume\,\,of\,\,cone=1526.62

Rounding off to the nearest tenth:

Volume\,\,of\,\,cone=1527.1\,\,cm^3

So, Option C is correct.

Keywords: Volume of cone.

Learn more about Volume of cone at:

  • brainly.com/question/12497249
  • brainly.com/question/6443737

#learnwithBrainly

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Answer:

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Step-by-step explanation:

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Compare to vertex form:

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we see that (h, k) = (-2, 6) . . . . the vertex

_____

<em>Additional comment</em>

The value added and subtracted is the square of half the x-coefficient. Inside parentheses, that value "completes the square". Outside parentheses, that value ensures the overall function remains unchanged.

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Step-by-step explanation:

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Problem 3.3.9 • (a) Starting on day 1, you buy one lottery ticket each day. Each ticket is a winner with probability 0.1. Find t
strojnjashka [21]

Answer:

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b)

c)

Step-by-step explanation:

a) Let p be  the probability of winning each ticket be = 0.1

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The last trial must be success whose probability is p = 0.1 and in the remaining (x + r- 1) ( x+ 4 ) trials we must have have (4) successes whose probability is given by:

\binom{x+r-1}{r-1}*p^{r-1}*q^{x} = \binom{x+4}{4}0.1^{4}*0.9^{x} ; x =0, 1, .........

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where;

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The probability mass function of K = P(K=k) = \binom{k-1}{4}0.1^{4}*0.9^{k-5} ; k =5,6,...

b)

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P(X=x) = \binom{x-1}{r-1}(1-p)^{x-r}p^r

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c)  

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also success probability is 0.01.

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