Hello,
6b) (i) As you can see, in the first year the price drops from 27,000 to 17,000. (Look at year 0-1 on the x axis). To find the percentage drop, find the difference between the two values and divide it over the initial value of 27,000.
So, the percentage drop in the first year is:
(27000-17000) / (27000) = 0.37, or a 37% drop
The answer is 37%.
(ii) For this question, we basically have the same process as the previous question except for the second year.
From year 1 to year 2, the value starts at 17,000 and ends at 15,000.
To find the percentage drop, we do:
(17000 - 15000) / (17000) = 0.118 ≈ 0.12, or a 12% drop
The answer is 12%.
6c) To find the percentage depreciation over the first 5 years, we look at the initial value (x = 0) and the value after 5 years (x = 5), and use these values in the same percentage formula we have been using.
The initial value of the car is 27,000, and after 5 years the value is 8,000.
This is a percentage drop of (27000 - 8000) / (27000) = 0.70, or a 70% drop.
The answer is 70%.
Hope this helps!
He brought home 6 pints of milk home
hope it helps
$20.00 ≥ 7.50+1.25x
subtract 7.50 from both sides
20-7.50=12.50
12.50=1.25x
12.50/1.25=10
x= 10 rides
The correct answer is: [C]: " 5 " .
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→ " a = 5 " .
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Explanation:
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Given: " a + 1 <span>− 2 = 4 " ; Solve for "a" ;
4 + 2 = 6 ;
6 </span>− 1 = 5 ; → a = 5 ;
To check our work:
5 + 1 − 2 = ? 4 ?? ;
5 + 1 = 6 ;
6 − 2 = 4. Yes!
So the answer is: [C]: " 5 ".
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→ " a = 5 " .
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