30.00x3=90.00$+25.00$=115.00$ so it has to be 115.00)
Answer:
The number of students that bring their lunches is 12
Step-by-step explanation:
Let
x -----> the number of students that bring their lunches
y -----> the total number of students in a class
we know that
The number of students that bring their lunches divided by the total number of students in a class must be equal to 3/8
-----> equation A
-----> equation B
substitute the value of y in equation A and solve for x
therefore
The number of students that bring their lunches is 12
The probability of being 25-35 years and having a haemoglobin level above 11 is 34%.
The probability of having a haemoglobin level above 11 is 36%.
Being 25-35 years and having a hemoglobin level above 11 are not dependent on each other.
<h3>What are the probabilities?
</h3>
Probability determines the odds that a random event would occur. The odds of the event happening lie between 0 and 1.
The probability of being 25-35 years and having a haemoglobin level above 11 = number of people between 25 - 35 that have a level above 11 / total number of people between 25 - 35
44 / 128 = 34%
The probability of having a haemoglobin level above 11 = number of people with a level above 11 / total number of respondents
153 / 429 = 36%
To learn more about probability, please check: brainly.com/question/13234031
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Answer:
Step-by-step explanation:
Hello!
I'll express all the given percentages as probabilities:
Given the events:
Banking online (Bo)
Under the age of 50 (<50)
P(Bo)= 0.30
P(<50)= 0.40
P(Bo ∩ <50)= 0.25
1) What percentage of adults do not conduct their banking online?
The event "adults that do not conduct their baking online" is the complement of the event "adults that conduct their baking online" Symbolically 
P(
)= 1 - P(Bo)= 1 - 0.30 = 0.70
2) What type of probability is 25%?
The probability P(Bo ∩ <50)= 0.25 is a joint probability, it indicates the intersection between both events.
3) Construct a contingency table showing all joint and marginal probabilities.
Check attachment.
4) What is the probability that an individual conducts banking online given that the individual is under the age of 50?
Symbolically:
P(Bo/<50)= <u> P(Bo ∩ <50) </u> = <u> 0.25 </u> = 0.625
P(<50) 0.40
I hope it helps!