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3 years ago

Select the expression equal to

Mathematics

2 answers:

lys-0071 [83]3 years ago

6 0

Answer:

$5\sqrt{3}$

Step-by-step explanation:

$\sqrt{75}$

There is a perfect square of 25, so we remove it.

$=\sqrt{25\times3}$

Split the radical sign for both radicand.

$=\sqrt{25}\times \sqrt{3}$

Simplify the perfect square;

$5\sqrt{3}$

snow_lady [41]3 years ago

4 0

Answer:

i believe the answer is the 4th one. sorry, i cant figure out how to write it on computer...

3 x 25

3 x 5 x 5

3-/5 (i tried)

1. if there are an even number of the same number on the right side of the square root, then it just becomes one and stays on the right.

2. if theres just one of that number on the right side, then it goes on the left, because there isnt anything to match it.

3. if there is an odd number of the same number on the right side, then one goes on the left, and the rest follow the even rule (#1)

idk if that made sense, but its how my mind works. if you need a clear version, then dont be afraid to ask. ill try to clear it as simply as i can. :P

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Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

$y=3(x+5)^2-4$

Extreme value:

$(h,k)=(-5,-4)$

Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

$y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71$

$y=3(x+5)^2-75+71$

So, we get equation as

$y=3(x+5)^2-4$

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

now, we can compare and find h and k

$y=3(x+5)^2-4$

we get

h=-5

k=-4

so, extreme value of this equation is

$(h,k)=(-5,-4)$

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3 years ago

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tigry1 [53]

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How do you solve U/6=9

notsponge [240]

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vichka [17]

Answer:

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Step-by-step explanation:

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2 years ago

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