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babymother [125]
3 years ago
9

Select the expression equal to

Mathematics
2 answers:
lys-0071 [83]3 years ago
6 0

Answer:

5\sqrt{3}

Step-by-step explanation:

\sqrt{75}

There is a perfect square of 25, so we remove it.

=\sqrt{25\times3}

Split the radical sign for both radicand.

=\sqrt{25}\times \sqrt{3}

Simplify the perfect square;

5\sqrt{3}

snow_lady [41]3 years ago
4 0

Answer:

i believe the answer is the 4th one. sorry, i cant figure out how to write it on computer...

75

3 x 25

3 x 5 x 5

3-/5 (i tried)

1. if there are an even number of the same number on the right side of the square root, then it just becomes one and stays on the right.

2. if theres just one of that number on the right side, then it goes on the left, because there isnt anything to match it.

3. if there is an odd number of the same number on the right side, then one goes on the left, and the rest follow the even rule (#1)

idk if that made sense, but its how my mind works. if you need a clear version, then dont be afraid to ask. ill try to clear it as simply as i can. :P

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today's local newspaper lists 20 stocks of local interest. of those stocks ten increased five decreased and five remained unchan
coldgirl [10]

Answer:

P(x=2) = 0.2368

Step-by-step explanation:

given data

stocks of local interest N = 20

stocks increased K = 10

stocks decreased =  5

remained unchanged = 5

solution

we take here no of stock that are increased randomly n = 2

so here Hypergeometric random variable can take integer value

{max(0, n+k - N ), min(n,K) } = {0,2}

so here

P(x=2)

so

P(x=k)  = \frac{(^K_k)\times (^{N-K}_{n-k}) }{(^N_n)}      .......................1

P(x=2 ) = \frac{(^{10}_2)\times (^{20-10}_{2-2}) }{(^{20}_2)}    

solve it we get

P(x=2 ) = 0.236842

now we use excel function as

HYPGEOM.DIST (k,n,N.cumulative)   .....................2

so it will be

HYPGEOM.DIST (2,2,10,,false)

we get

HYPGEOM.DIST (2,2,10,,false)  = 0.236842

so

P(x=2) = 0.2368

4 0
3 years ago
Directions: Find the complemen
andre [41]

Given:

The angles are:

Example 54^\circ

1. 63^\circ

2. 87^\circ

3. 45^\circ

4. 72^\circ

5. 5^\circ

To find:

The complimentary angle of the given angles.

Solution:

If two angles are complimentary, then their sum is 90 degrees.

Example: Let x be the complimentary angle of 54^\circ, then

x+54^\circ=90^\circ

x=90^\circ -54^\circ

x=36^\circ

Similarly,

1. The complimentary angle of 63^\circ is:

90^\circ -63^\circ=27^\circ

2. The complimentary angle of 87^\circ is:

90^\circ -87^\circ=3^\circ

3. The complimentary angle of 45^\circ is:

90^\circ -45^\circ=45^\circ

4. The complimentary angle of 72^\circ is:

90^\circ -72^\circ=18^\circ

5. The complimentary angle of 5^\circ is:

90^\circ -5^\circ=85^\circ

Therefore, the complimentary angles of 54^\circ, 63^\circ, 87^\circ, 45^\circ, 72^\circ, 5^\circ are 36^\circ, 27^\circ, 3^\circ, 45^\circ, 18^\circ, 85^\circ respectively.

6 0
3 years ago
What is the value of x
mezya [45]

Answer:

x=9.5

Step-by-step explanation:

In order to find the answer, we know that 6x + 4x - 5 = 90

Next we want to combine like terms: 10x - 5 = 90.

Now we have to add 5 to 90 in order to get x on its own.  10x = 95

Now solve for x by dividing 95 by 10: x=9.5

4 0
2 years ago
Read 2 more answers
What is 7 +2 = x-4/2​
madam [21]

Answer:

The answer is 11.

Step-by-step explanation:

We will use PEMDAS in this situation.

 7 + 2 = x - 4 / 2

 7 + 2 = x - 2             [divide first

 9 = x - 2                   [add the 7 and 2]

+2       +2                   [the 2 cancels out]

 11 = x

Your answer is 11.

I hope this helped!

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>
7 0
3 years ago
Find the area and perimeter of the shape below. Help plzzz.
kozerog [31]
Find the area of each shape and add.Let's start with the first semi-circle(half-circle)
If the area of a circle is πr² , then the area of a semi-circle is 1/2πr² where is 22/7 or 3.14, and r is the radius which is 1.8 meters
A=1/2πr²
A=1/2*22/7*1.8*1.8
A=5.09 m²(rounded to nearest hundredth)
Since the semi-circles are two and have the same radius, multiply the area of the first one by two or go through the same process again.
So 5.09 *2=10.18meters square is the area of the two semi-circles
Now, let's find the area of a rectangle  which is length times width, where length is 6 meters and width is (1.8+1.8, because 1.8 is half the width)=3.6 meters
A=l*w
A=6*3.6
A=21.6meters square
Therefore the area of the shape is 10.18m²+21.6m²=219.888m²
4 0
3 years ago
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