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julsineya [31]
2 years ago
8

Three out of five attempts, Kyan ski's a 180° perfectly. What percent would describe his success?

Mathematics
1 answer:
trapecia [35]2 years ago
5 0

Divide 3 by 5 and then multiply by 100 to get percentage.

3/5 = 0.60 x 100 = 60%

Answer: 60%

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padilas [110]

Answer:

8 lines in the symentery

Step-by-step explanation:

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4 0
2 years ago
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Laura can weed the garden in 1 hour and 20 minutes and her husband can weed it in 1 hour and 30 minutes. How long will they take
Harrizon [31]
<h2>Hello!</h2>

The answer is:

It will take 42.35 minutes to weed the garden together.

<h2>Why?</h2>

To solve the problem, we need to use the given information about the rate for both Laura and her husband. We know that she can weed the garden in 1 hour and 20 minutes (80 minutes) and her husband can weed it in 1 hour and 30 minutes (90 minutes), so we need to combine both's work and calculate how much time it will take to weed the garden together.

So, calculating we have:

Laura's rate:

\frac{1garden}{80minutes}

Husband's rate:

\frac{1garden}{90minutes}

Now, writing the equation we have:

Laura'sRate+Husband'sRate=CombinedRate

\frac{1}{80}+\frac{1}{90}=\frac{1}{time}

\frac{1*90+1*80}{7200}=\frac{1}{time}

\frac{170}{7200}=\frac{1}{time}

\frac{17}{720}=\frac{11}{time}

\frac{17}{720}=\frac{1}{time}

\frac{17}{720}*time=1

time=1*\frac{720}{17}=42.35

Hence, we have that it will take 42.35 minutes to weed the garden working together.

Have a nice day!

8 0
3 years ago
Charge q is one unit of distance away from the source charge s. Charge p is two times further away. The force exerted between S
finlep [7]

Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S and q is _____ the force exerted between S and p

a. 1/2

b. 2 times

c. 1/4

d. 4 times

Answer:

4 times

Step-by-step explanation:

Given the following :

Distance between q and S (r) = 1 unit

Distance between P and S (r) = 2 × 1 unit = 2

According to coliumbs law:

F = Ke(q1q2) /r^2

Where F = electrostatic force, Ke = coloumbs constant

q1,q2 = charges, r = distance between two charges

For q and S :

Fsq = Ke(q1q2) / 1^2

Fsq = Ke(q1q2) - - - - - equation 1

For P and S :

Fsp = Ke(q1q2) / 2^2

Fsp = Ke(q1q2) / 4 - - - - - equation 2

Dibiding equation 1 by equation 2

Fsq/Fsp = Ke(q1q2) / Ke(q1q2)/4

Fsq / Fsp = Ke(q1q2) × 4 / Ke(q1q2)

Fsq / Fsp = 4 / 1

Using cross multiplication

Therefore, Fsq = 4 × Fsp

7 0
3 years ago
6. Matthew is planning to build a right triangular
saul85 [17]
The answer to this question will be B
8 0
3 years ago
Can you show work for B?
malfutka [58]

Answer:

dis confusing

Step-by-step explanation:

3 0
3 years ago
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